I would say it does not. The lack of agreement with the earlier values for Jan-Sep is a bad sign. The large negative value for Nov suggests that there’s something wrong. What do these numbers represent? Is a negative value physically possible? It’s a mistake to treat a function like a black box. I could … Read more
You have a few problems… You have this interface: interface Joke{ id: number; value: string; } what you are receiving is much more properties, so you’d need to pick the properties you want: getRandomJokes(){ return this.http.get(‘https://api.chucknorris.io/jokes/random’) .map(res => res.json()); // pick the properties you want/need .map(joke => <Joke>{id: joke.id, value: joke.value}) } Then you have … Read more
Put a as the animal property of call, and b as the mood property of call: call = { animal: A, mood: B }; If the arrays are meant to be of strings, then make sure to put ‘ around each string, like A = [‘cat’, … 0 solved Make two arrays into json data
This should do it. If CategoryNAME coming back as null, then you’re doing a LEFT OUTER join and have referential integrity issues. CREATE PROCEDURE usp_OrderDetails_SelectByOrderId @OrderID INT AS BEGIN SELECT P.ProductId, OD.Qty, P.Price, C.NAME AS CategoryNAME FROM tblProducts P INNER JOIN tblCategories C ON P.CategoryId = C.CategoryId INNER JOIN tblOrderDetails OD ON P.ProductId = OD.ProductId … Read more
Try this: if let scene = SCNScene(named: “Models.scnassets/CDMTEST1″){ sceneView.scene = scene } you need to pass a value not a optional since SCNScene(named: “Models.scnassets/CDMTEST1”) is optional since may return nil since it fails. 1 solved Value of optional type must be unwrapped to a value of type [duplicate]
MessageBox is a modal dialog, the function does not return until the dialog has been closed. Multiple MessageBoxs can only be created if you have multiple threads in your process. MessageBox is a special version of DialogBox. You can use CreateDialog to create modeless dialogs but you should not show many dialogs to the user … Read more
Just map over the array and do Math.pow(int,power) but multiplication is faster so do value * value in the .map function const realNumberArray = [4, 5.6, -9.8, 3.14, 42, 6, 8.34, -2]; // your array const squares = realNumberArray.filter(x => x > 0 && Number.isInteger(x)); // your filter function const squared = squares.map(val => val*val) … Read more
You seem not to have understood how the CPU and the bus are working: As you knows network i/o is based on nic interrupt. An interrupt is a mechanism which is starting a short program whenever the hardware (for example the network card) requests the CPU to do so. An interrupt only starts this short … Read more
you are recreating the arr 11 time in your loop i think you meant to do this : //the error is generated because you are trying to access an element out of bounds because your declaration is wrong std::vector<MyClass> arr; for(unsigned long long i = 0 ; i<=10;i++){ arr.emplace_back( 10,20+i); std::cout << arr[i].ggg; } 0 … Read more
i had this issue before, using wordpress in a laravel application Built on eloquent and can be installed via composer. it provides an easy way to pull data to and fro- a wordpress database to your laravel application. composer require jgrossi/corcel here’s the link to it WordPress backend with Laravel, i hope this helps. 1 … Read more
Just use the querySelectorAll() method instead and target the second li element like this: document.querySelectorAll(“#list li”)[1].onclick = () => { console.log(“Biker Jacket”); }; <h3>Shirts</h3> <ul id=’list’> <li>Biker Jacket</li> <li>Mens Shirt</li> </ul> 1 solved How can I console.log the second li element using javascript onclick
The total variable will contain the number of unique characters in the array str. This happens because you increment the count(total+=!used[str[i]-‘a’]) only if you haven’t already marked the character as visited. If you incremented it, you mark it as such in the next line (used[str[i]-‘a’]=1) so that you wont count it again. The notation str[i]-‘a’ … Read more
Use a for-loop that pushes to an array: function count(n){ let arr = []; for (let i = 1; i <= n; i++){ arr.push(i); } return arr; } console.log(count(5)); console.log(count(7)); solved JavaScript, how to create an array that sequentially counts till N? [closed]
This line: printf(” %d / %d”, num1/num2); The first ‘%d’ is the result of num1/num2 and that’s enough. The second %d and the “https://stackoverflow.com/” character should not be here. Change it to: printf(” %d “, num1/num2); Additionaly, for your purpose, the switch case structure is more suitable for code readability (and better optimization too I … Read more
Contract compliance for Java classes is checked statically by the compiler. Virtual machine is responsible for bytecode loading, verifying and running. It does not check whether some class implements all methods of some interface. 3 solved Why does Java allow you to create an object from a class that implements partially an interface if it … Read more