[Solved] How to square integers inside an array?

by


Just map over the array and do Math.pow(int,power) but multiplication is faster so do value * value in the .map function

const realNumberArray = [4, 5.6, -9.8, 3.14, 42, 6, 8.34, -2]; // your array
const squares = realNumberArray.filter(x => x > 0 && Number.isInteger(x)); // your filter function
const squared = squares.map(val => val*val) // map and do val*val to get an array of elements of val*val
console.log(squared) // log it

Your code becomes 

const realNumberArray = [4, 5.6, -9.8, 3.14, 42, 6, 8.34, -2];

const squareList = (arr) => {

  "use strict";
  const squaredIntegers = realNumberArray.filter(x => x > 0 && Number.isInteger(x));
  const squared = squaredIntegers.map(val => val*val)
  return squared;
};

// test your code

const squaredIntegers = squareList(realNumberArray);

console.log(squaredIntegers);

solved How to square integers inside an array?