There are a few different components to this problem. First, how do you split the receipt into each individual company. Next you need to be able to parse the company’s ID. Finally you need to be able to parse the quantity, cost, and total cost from a line item. Splitting Receipts Your method of splitting … Read more
You can’t define a module using module Auth(): irb(main):001:0> module Auth() irb(main):002:1> end SyntaxError: (irb):1: syntax error, unexpected ‘\n’, expecting :: or ‘[‘ or ‘.’ and irb(main):001:0> module Auth() irb(main):002:1> def login(id) irb(main):003:2> end irb(main):004:1> end SyntaxError: (irb):1: syntax error, unexpected ‘\n’, expecting :: or ‘[‘ or ‘.’ (irb):4: syntax error, unexpected keyword_end, expecting end-of-input … Read more
Here’s a simple random string generator in a working snippet so you can see what it generates: function makeRandomStr(len) { var chars = “abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789”; var result = “”, rand; for (var i = 0; i < len; i++) { rand = Math.floor(Math.random() * chars.length); result += chars.charAt(rand); } return result; } document.getElementById(“run”).addEventListener(“click”, function() { var … Read more
There’s a few problems here. Firstly, you don’t ever finish your onClick attribute, so this is likely to result in JavaScript errors. Check this in your console. If you are using onClick it is best to keep JavaScript brief in here — write a JavaScript function, and call it from this event. Any PHP you … Read more
Without seeing any code, you probably want to flip your loop: for(int i = 0; i < cards.Count; i++) to for(int i = (cards.Count – 1); i >= 0; i–) But please share some code, so we can help. Edit: Corrected Loop. 4 solved Right to left letters in cards Unity
You mean like this? html <div id=”menu”> <ul> <li>one</li> <li>two</li> <li>three</li> <li>four</li> <li>five</li> <li>six</li> <li>seven</li> <li>eight</li> <li>nine</li> <li>ten</li> </ul> </div> jquery var i = 0; var count = 5; $(“#menu ul li”).each(function () { if (i < count) { i++ } else { i = 1; } $(this).addClass(“item-” + (i)); }); 1 solved I want … Read more
From public function editQuestion(Question $slug) { return view(‘questions.editquestion’,[ ‘slug’ => $slug ]); } you are injecting Question model in editQuestion(Route-model binding), so you should pass your question class instance in your form too. <form action=”{{ route(‘edit.question’, $show) }}”> <button type=”submit” class=”text-blue-500″>Edit Question</button> </form> or <form action=”{{ route(‘edit.question’, [‘question’ => $show]) }}”> should work fine. solved … Read more
You have two issues: 1) Your closing } for the try is inside the if. 2) You are not properly calling the constructor of IllegalArgumentException. Do `throw new IllegalArgumentException(); In the future, you should read and try to understand the compiler message. It is most likely telling you exactly what there errors are and where. … Read more
Mikel, you can’t achieve a silk-screen effect using CSS and a single image. It’s not going to happen any time soon, in any cross-browser compatible way. Maybe, eventually, when you can custom-program CSS filters using HLSL or similar… But for the time-being, even with near-ish-future CSS-filters, I don’t think that they’re going to offer silk-screen, … Read more
Take a look at Java Collections. You can use a List like Luiggi suggested, or you may want to use a Map so that you can look them up by name or Id. import java.util.HashMap; import java.util.Map; public class Employee { private final String name; private final int Id; private static Map<String, Employee> employeesByName = … Read more
I solved it using “order by col_1_0_” in above query.. because hibernate creates column with names col_0_0_, col_1_0_, col_2_0_ and so on.. so if you just need to know the order of your column and add it to order by accordingly.. Thanks. amar4kintu 1 solved HQL Order by query giving problem
Let’s say your data.frame is called dd. If you want to see the total number of weather delays for each month across all years you can do delay <- aggregate(WeatherDelay~Month, dd, sum) delay[order(-delay$WeatherDelay),] 1 solved finding the most frequent item using bigmemory techniques and parallel computing? [closed]
Dude. Perhaps you should consider making use of named parameters. What is the “Named Parameter Idiom” http://www.parashift.com/c++-faq/named-parameter-idiom.html Or if you use Boost, consider using the following. The Boost Parameter Library http://www.boost.org/doc/libs/1_55_0/libs/parameter/doc/html/index.html Or, if you do not like that, a single parameter that is a map of a string to a union (or any, also part … Read more
For a given domain, e.g. yahoo.com you can google-search site:yahoo.com; at the top of the results it says “About 141,000,000 results (0.41 seconds)”. This includes subdomains like www.yahoo.com, and it.yahoo.com. Note also that some websites generate pages on the fly, so they might, in fact, have infinite “pages”. A given page will be calculated when … Read more
It simply means: Return the property file as InputStream from the ClassLoader the current thread of my application is running from (in loose english). 4 solved Usage of Thread.currentThread().getContextClassLoader().getResourceAsStream(“system.properties”) [closed]