[ad_1] Since the length of the array is not known at compile time, you can not use an automatic array. The array has to be allocated dynamically. The simplest solution to copy a string into an array would be to use std::vector. However, I suspect that your desire to create an array from a string … Read more
[ad_1] You aren’t actually printing the result; you’re just calling the add() method. Try: System.out.println(m.add()); 0 [ad_2] solved Java multiple class addition
[ad_1] You can do this with ParseExact by specifying the format like this: var datestring = “9/4/2015 12:09:06 PM”; var dt = DateTime.ParseExact(datestring, “M/d/yyyy h:mm:ss tt”, CultureInfo.InvariantCulture); Depending if its 9th april or 4th september you can use d/M or M/d. 3 [ad_2] solved Converting this string to a date [closed]
[ad_1] You need a little more debugging here. For instance, check that your split gives you what you want. Second, please read https://stackoverflow.com/help/mcve — this lists our expectations for posting. Giving the actual input and error message would have given you an answer much sooner: you fed a list to fnmatch, which expects a string. … Read more
[ad_1] You can process the input number one by one. int i = 0; // variable for loop control int num_of_odds = 0; // variable for output while (i < 20) { int a; cin >> a; if (a % 2 == 1) num_of_odds++; i++; } cout << “there are ” << num_of_odds << ” … Read more
[ad_1] You are not creating any Person objects. You are creating a Person array with space to hold some Person objects, but I will bet you pounds to pence that you aren’t populating that array with a single Person. It is an empty array. You might write: Person[] persons = new Person[3]; persons[0]=new Person(); Now … Read more
[ad_1] Once you have your map constructed, you can access a value of the map by providing the key. The syntax is: value := myMap[myKey] The key’s type can be any type that can be evaluated by a comparison operator ( >=, ==, <=, etc…). For your example it looks like you are using strings … Read more
[ad_1] IE browsers up to IE8 do not support addEventListener (I’m assuming you meant the latest version you have when you said Internet Explorer Last version). attachEvent is the IE equivalent (well, not exactly equivalent). If your target browser is only IE8, you can just replace the addEventListeners with attachEvent calls, but a better option … Read more
[ad_1] for a link in HTML the code should be <a href=”https://stackoverflow.com/questions/29911714/{yourURL}”>TEXT HERE</a> But it would be more helpful if you posted up your code for us to see where the mistake is. 1 [ad_2] solved HTML content is displaying as plain text
[ad_1] For this, you should use generators. function generate_flavors* () { yield “Butter Cream”; yield “Chocolate”; yield “Vanilla”; yield “Red Velvet”; } Now you can create your array in any of several ways: console.log(Array.from(generate_flavors())) console.log(…generate_flavors()) console.log([for (flavor of generate_flavors()) flavor]) Hope that helps. 0 [ad_2] solved Create an Array and Populate it with values in … Read more
[ad_1] To keep records in a file, you write them to the file: fwrite(&variable, 1, sizeof(record), file_pointer); To read a record from a file: fread(&variable, 1, sizeof(record), file_pointer); To position to record Y in the file: fseek(file_pointer, (Y * sizeof(record)), SEEK_SET); If this is not helpful, please clarify “keep in a file”, or state why … Read more
[ad_1] This is a very concise list comprehension form, which is equivalent to the following: res = [] for value in db.cursor.fetchall(): pairs = [] for index, column in enumerate(value): pairs.append((columns[index][0], column)) d = dict(pairs) res.append(d) The res list is equivalent to what you wrote above. 1 [ad_2] solved Could you please explain this piece … Read more
[ad_1] From http://www.ecma-international.org/ecma-262/5.1/#sec-15.1.2.2 Step 8a: If R < 2 or R > 36, then return NaN. That’s why. It’s just a arbitrary rule to simplify implementation, probably. Edit: see comment for the probable reason. 7 [ad_2] solved How come parseInt wont convert to base 60? [closed]
[ad_1] a_collection.getInfo()[‘features’][0][‘bands’] or even better: a_collection.first().bandNames().getInfo() The following tutorial is also a useful source. https://colab.research.google.com/github/csaybar/EEwPython P.S. It is intentional to have the address attached to the hyperlink visible. As opposed to some thing like CLICK HERE. [ad_2] solved List of band names of image in Python [closed]
[ad_1] Likely it is a memory management issue. Are you abiding by rules set out in the Memory Management Programming Guide? Try: revising the memory management rules, make sure you are not using any objects that you don’t own, make sure you are retaining objects you want to keep (and releasing them appropriately afterwards); running … Read more