[ad_1] You check for the empty line after appending the splitted line to data. .split() on an empty line returns an empty list. x[0] on an empty list produces an IndexError. data +=[line.split()] # equal to data.append([]) if line ==”: ips=[ x[0] # Access to the first element of every list in data. for x … Read more
[ad_1] you should share what you have tried when asking a question this is not a code making site. we help you debug your pre-existing code. but anyway, here is an example of what you want to achieve ( i guess you are interested in the css-styles of the button eg shadows, borders etc. ) … Read more
[ad_1] It is not entirely clear what the conditions are. Based on your comments I think you look for the following regex: r”Профессиональная ГИС \”Панорама\” \(версия 12(\.\d+){2,}, для платформы \”x(32|64)\”\)” This will match any sequence of dots and numbers after the 12. (so for instance 12.4.51.3.002 is allowed), and furthermore both x64 and x32 are … Read more
[ad_1] So here we go. I will help you with such task. First get list of databases. Then get list of tables (parameter is Connection string, where you should add the name of the database you have choosen in your combobox. public List<string> GetDatabaseList() { List<string> list = new List<string>(); string conString = “Data Source=yourDataSource; … Read more
[ad_1] First you need to create an enumeration for the weekdays: extension Date { enum Weekday: Int { case sunday = 1, monday, tuesday, wednesday, thursday, friday, saturday } } Second create an extension to return the next weekday desired: extension Date { var weekday: Int { return Calendar.current.component(.weekday, from: self) } func following(_ weekday: … Read more
[ad_1] If you want to get the results of every iterations of a for loop into a list, you need a list to store the values at each iteration. import ipaddress user_input = input(“”) network = ipaddress.IPv4Network(user_input) ipaddresses = [] #initiate an empty list for i in network.hosts(): ipaddresses.append(i) print(ipaddresses) [ad_2] solved How to catch … Read more
[ad_1] def perfect(x): factor_sum = 0 for i in range(1, x-1): if x % i == 0: factor_sum = factor_sum + i if(factor_sum == x): return True return False print perfect(6) #Prints True print perfect(12) #Prints False print perfect(28) #Prints True [ad_2] solved Answer by python language [closed]
[ad_1] public class Demo { public static boolean contains(String str,char c){ //todo:check str for NullPointExecption int flag=0; for(int i=0;i<str.length();i++){ if(c==str.charAt(i)){ flag++; //if str contains char c,flag=flag+1 } if(flag>=2){ return true; //if flag>=2,return true } } return false; } public static void main(String[] args) { System.out.println(contains(“appple”, ‘p’));//result is true } } 7 [ad_2] solved Question >> … Read more
[ad_1] try this: const data = { “server”:”S1″, “timestamp”:”123456″, “data”:[ {“device”:”D1″, “price”:”50″}, {“device”:”D2″, “price”:”60″}, {“device”:”D3″, “price”:”70″} ] } result = {data: data.data.map(res=>({…res, …{‘timestamp’: data.timestamp, ‘server’: data.server} }))} console.log(result); 1 [ad_2] solved Json object with attributes + array, how to move the attributes inside the array?
[ad_1] The fact that the ids were the same implies that they are pointing on the same object. String in Python is immutable, you can’t assign to it’s indexes values. Immutability means that we can change the original object: # List is mutable l = [1, 2, 3] # That’s OK l[0] = 5 # … Read more
[ad_1] Edit Your code at value on both TextInput value={this.state.login} value={this.sate.password} [ad_2] solved Variables in state are not defined
[ad_1] This code should work for you. It makes use of the fact, that str is a pointer to the first character of the string. char *str = “Hello world”; /* * Uncomment if `str` could be `NULL`: * * if (str == NULL) { * fprintf(stderr, “Error: invalid string\n”); * exit(EXIT_FAILURE); * } */ … Read more
[ad_1] One of the shortest way would be to prepare a list/set of all the keys from all the dictionaries and call that key on all the dictionary in the list. list_of_dict = [{‘a’: 1, ‘b’: 2, ‘c’: 3}, {‘a’: 3, ‘b’: 5}, {‘k’: 5, ‘j’: 5}, {‘a’: 3, ‘k’: 5, ‘d’: 4}, {‘a’: 3}] … Read more
[ad_1] R00T CaUsE Adding <authorization> tag with the code shown in above question would make any anonymous user from accessing any page other than Login, as each request will be redirected to LogIn Page with no other content allowed from server including basic CSS. Suggested solution 1 on the web was to add <location> tag … Read more
[ad_1] I figure out the reason finally:It is because of the GameLayer instance A that used to register the PanGestureRecognizer and the GameLayer instance B which used to show the screen is not same instance.Such that processPanGesture() function is just change instance A’s currentPer,While what i print is instance B’s currentPe [ad_2] solved Why the … Read more