A typical fast solution to the gcd algorithm would be some iterative version like this one: def gcd(x, y): while y != 0: (x, y) = (y, x % y) return x In fact, in python you’d just use directly the gcd function provided by fractions module. And if you wanted such function to deal … Read more
Short answer: No If it was a division or multiplication by powers of 2, you could use bitwise shift operators to make it faster, but in this case, nothing is better than x = 128 – x 0 solved What is the quickest way to subtract a variable from a number and set the variable?
Use explode() to separate the hour / minute pieces, then do the math yourself: list( $hour, $min) = explode( ‘:’, “192:40”); list( $hour_sub, $min_sub) = explode( ‘:’, “02:30”); $result = ($hour – $hour_sub) . ‘:’ . ($min – $min_sub); echo $result; This will print: 190:10 If the time were to wrap around, ($min – $min_sub) … Read more
Something like this: select ( select sum(calculated_tax) from table_01 ) – ( select sum(deductible_tax) from table_02 ) as result 1 solved MySQL arithmetic subtraction
Its very simple you are not calculating applesToOrder and orangesToOrder again after user input so they are taking there previous values of 0, just put these lines just above your last JOptionPane statement and see the magic. applesToOrder = applesTheyNeed – applesTheyHave; orangesToOrder = orangesTheyNeed – orangesTheyHave; 1 solved subtraction not working in java program … Read more
Check it out: if use $date2 as 24:00 $date1 = new DateTime(’02:40′); $date2 = new DateTime(’24:00′); $finaldate = $date2->diff($date1); echo $finaldate->format(‘%h:%i’); // 21:20 But if use $date2 as 00:00 $date1 = new DateTime(’02:40′); $date2 = new DateTime(’00:00′); $finaldate = $date2->diff($date1); echo $finaldate->format(‘%h:%i’); //02:40 1 solved Time Subtract in PHP
UPDATE b SET b.c1 = b.c2 – b.c3 FROM a JOIN b ON … JOIN c ON … solved SQL Join with subquery