[ad_1] To replace a backslash you have to escape it with another backslash. So in your example to replace \\ you have to escape each of them with backslash, so you can try this $replaced = str_replace(‘\\\\’, ‘\\’, $str1); [ad_2] solved How can I replace a blackslash character? [duplicate]
[ad_1] String.trim() method remove trailing and leading white spaces from the string. but since the string you are testing doesn’t have any trailing or leading white spaces, the below two will certainly return the same string. str.replaceFirst(“(.*)<?xml”,”<?xml”); str.trim().replaceFirst(“(.*)<?xml”,”<?xml”) However, your regular expression only removes leading white spaces, so if the testing string has trailing white … Read more
[ad_1] First, as was pointed out in the comments, if you’re looking to reduce the size, comments should be stripped. function convertComment(str){ if(str.substring(0,2) === ‘//’){ str=”/*” + str.substring(2) + ‘ */’; } else { str = false; } return str; } Your example code looked like JQuery, so if you were looking for PHP, here … Read more
[ad_1] You can use: $strPar = “12345|12345|12345|12345 12345|12345|12345|12345 12345|12345|12345|12345”; $strpar = str_replace(“\n”, “|”, $strPar); Make sure the \n character is in double quotes 2 [ad_2] solved Replace ‘New Line’ with ‘|’ [closed]
[ad_1] Based on the conditions you mentioned you can do something like below. Find the word count and then check is home available in the string and then find the index of the house . So then you can check does that index match to last index of the word array (count($wordArray)) – 1) $string1 … Read more
[ad_1] I think using Regular Expression works better. private static String setSize(String htmlString) { String reg = “size=”[0-9]+””; Pattern pattern = Pattern.compile(reg); Matcher matcher = pattern.matcher(htmlString); while (matcher.find()) { String sizeString = matcher.group(); pattern = Pattern.compile(“[0-9]+”); Matcher numMatcher = pattern.matcher(sizeString); if (numMatcher.find()) { String size = numMatcher.group(); int realSize = Integer.parseInt(size); int resultSize = realSize … Read more
[ad_1] Most Unicode characters have multiple versions that can look very alike. For example: 1????１①⑴ var s = “æӕ”.Replace(“æ”, “ae”); // s = “aeæ” var v = “æӕ”.Select(c => (int)c).ToArray(); // { 230, 1237 } I consider it a good practice to expect the unexpected (especially when it comes to user input) var s = … Read more