[ad_1] Use a sql select query similar to this…. select * from EmployeeDetails ed left join EmployeeEntries ee on ee.EmpId = ed.EmpId Note that this query will return all entries for each employee and each record will have the employee details as well. That means the employee details will be repeated for each entry the … Read more
[ad_1] I’m quite sure this query will work; meaning that it won’t return an error but I’m not certain if it will return correct result as what you intended: SELECT s.Name, SUM(p.Note=5)/COUNT(*) as Anteil FROM Studenten s JOIN pruefen p ON p.MatrNr = s.MatrNr GROUP BY s.Name ORDER BY Anteil DESC, s.Name ASC; If this … Read more
Introduction [ad_1] ASP.NET MVC is a powerful web development framework that allows developers to create dynamic, data-driven web applications. It is a great platform for creating complex queries that can be used to retrieve data from a database. In this article, we will discuss how to create complex queries in ASP.NET MVC and how to … Read more
[ad_1] Forget all you learnt with ASP and VB apart from the base concepts like layers and learn about MVC, MVVM and LINQ, probably with Entity Framework for the backend. 0 [ad_2] solved ASP.NET MVC – Complex Queries [closed]
[ad_1] You can use a recursive CTE: with dates as ( select cast(getdate() as date) as dte union all select dateadd(day, -1, dte) from dates where datediff(day, dte, getdate()) <= 4 ) select * from dates order by dte desc; Obviously, you can reference any other date you want instead of getdate(). Your example suggests … Read more
[ad_1] Try this, SELECT HOTELNAME , ROOMTYPE , CONCAT(NIGHTS,’ NIGHTS ‘,ACCESSIBILITY) AS NUM_OF_NIGHTS FROM HOTEL, ROOM, BOOKING WHERE ACCESSIBILITY=’N’ OR ROOMTYPE=’DOUBLE’ ORDER BY NIGHTS DESC LIMIT 2 2 [ad_2] solved Select 2 maximum values in SQL with concatenation
[ad_1] You need to use JOIN to join both tables. SELECT * FROM dbo.bac A INNER JOIN dbo.data B ON B.counter = A.counter this should do it, but you need to filter your records as needed. 0 [ad_2] solved Merging tables in SQL Server
[ad_1] Extending the answer to this question: payment distrubution oracle sql query You can still use the SQL MODEL clause. In this version, you need separate calculations for each distinct account_num. You can achieve this using the PARTITION keyword of the SQL MODEL clause to partition by account_num. Like this (see SQL comments for step-by-step … Read more
[ad_1] First, figure out which records need to be updated: select * from tbl_order o inner join tbl_group g on g.grp_id = o.grp_id inner join tbl_indicator i on i.grp_nbr = g.grp_nbr and i.sect_nbr = g.sect_nbr where g.indicat != i.indicat Now, modify the query to update those records with the correct grp_id. Notice that I’ve added … Read more
[ad_1] SELECT fname,CASE WHEN fname=”A” THEN budget/2 WHEN fname=”B” THEN budget/4 WHEN fname=”C” THEN budget/6 END FROM tableName [ad_2] solved How to calculate with multiple value in SQL [closed]
[ad_1] Your query is referencing return_date, which isn’t a column in the airport_car_parking table. As for the logic of the query, you want to make sure that the $departure_date isn’t between any row’s departure_date or arrival_date. I would recommend the following query – $chk_date_sql=”SELECT * FROM airport_car_parking WHERE ‘$departure_date’ BETWEEN departure_date AND arrival_date;”; And then … Read more
[ad_1] The user that runs the MySQL daemon doesn’t have permission to write to your database directory. If you’re using a standard installation with default settings, the following command should fix that (edited to add sudo based on your edited output: if you can run as root, leave off the sudo): sudo chown -R mysql:mysql … Read more
[ad_1] Your code was missing some curly brackets ( {} ): include (“../dbconnect.php”); $sql=”SELECT c.endofmonthform, c.startofmonthform, c.email, c.id, c.formlevel, c.mastersite, c.opmanager, u.userEmail FROM `clients` as c LEFT JOIN `users` as u on c.opmanager = u.userName WHERE endofmonthform=”22/09/2016″”; //TODAYS DATE BACK HERE! $result=mysql_query($sql); while($row=mysql_fetch_array($result)){ $enddate = $row[‘endofmonthform’]; // End $startdate = $row[‘startofmonthform’]; // Start $email = … Read more
[ad_1] ‘Transaction’ is a pair of take + return. It’s identity is computed from source data so OPERATORs could be grouped the way you need. The query may fail on data with unpaired OPERATORs. declare @tbl table ( OPERATOR int, PRODUCT varchar(50), [USER NAME] varchar(100), [TIME STAMP] datetime); insert into @tbl(OPERATOR, PRODUCT, [USER NAME], [TIME … Read more
[ad_1] Try this one – CREATE FUNCTION dbo.udf_getCountCallOnDate ( @DateFrom DATETIME , @DateTo DATETIME ) RETURNS INT AS BEGIN RETURN ( SELECT SUM(CallsTakenOnDate) FROM dbo.PhoneCalls WHERE DateOfWork BETWEEN @DateFrom AND @DateTo ) END SELECT DateOfWork = CONVERT(VARCHAR(10), t.DateOfWork, 111) , [Count] = SUM(t.CallsTakenOnDate) FROM dbo.PhoneCalls t WHERE DateOfWork BETWEEN @DateFrom AND @DateTo ORDER BY t.DateOfWork … Read more