Without LEFT JOIN See demo SQL Fiddle SELECT u.id, (SELECT w.wink_flag FROM winks w WHERE w.to_id = u.id GROUP BY w.to_id) AS WINK_FLAG, (SELECT f.fav_flag FROM favourite f WHERE f.to_id = u.id GROUP BY f.to_id) AS FAV_FLAG FROM users u WHERE u.id != 56 0 solved There are 3 tables users,winks and favourite [closed]
with cte as ( select * — get min & max per date ,min(time) over (partition by cast(time as date)) as mintime ,max(time) over (partition by cast(time as date)) as maxtime from tab ) select * from cte where time in (mintime,maxtime) 1 solved how can i show the last event of each date in … Read more
Here’s a great answer from the DuckDB people: Two functions will do the trick for you! String_split, and unnest. Unnest is a special function that takes lists and creates a separate row for each element. With lists_split_into_rows as ( select col1, unnest(string_split(col2, ‘ ‘)) as new_column from my_table ) Select new_column, count(*) as my_count from … Read more
You should join two tables using ‘inner join’ and you have to use a ‘where’ condition. In where condition use ‘AND’ to check its the same person using the employee id and then sum the total working hours. solved database view creation issue
I’ll take a stab at your problem. This is only a guess, based on the query you provided. A complete question would have described what exactly you mean by a duplicate row. delete from Registrations where exists ( select 1 from Registrations r2 where r2.UserItemId = Registrations.UserItemId and r2.CourseOfferingId = Registrations.CourseOfferingId and r2.Id < Registrations.Id … Read more
It will not work because you are trying to update one column with multiple values. i.e. status is one column while * will give you multiple columns. set status = (select * Based on OP’s edit, SQL will be : UPDATE TCB SET TCB.STATUS = TE_SUM_O.STATUS FROM T_CARTON_BOX TCB INNER JOIN ( SELECT TE_SUM.CARTON_BOX,(CASE WHEN … Read more
https://www.codeschool.com/search?utf8=%E2%9C%93&loc=hero&query=sql Code school is a really good introduction to most concepts regarding SQL, but it is only really possible to have a really good understanding if you truly start with the basics so I would suggest starting here and then spending quite a few hours just messing around with an sql database of your own. … Read more
Your current syntax problem is with the @count = @count + 1; which needs to be set @count = @count + 1. But… There is no need for a loop. You can simply do one big insert directly, like: insert into your_table (fk_col, other_col1, other_col2) select pk_col, ‘something’, ‘something else’ from your_other_table If you need … Read more
Maybe like this? SELECT CPR_ENTITIES.ENTITY_ID, CPR_ENTITY_ATTRIBUTE.STRING_VALUE FROM CPR_ENTITIES LEFT JOIN CPR_ENTITY_ATTRIBUTE ON CPR_ENTITIES.ENTITY_ID = CPR_ENTITY_ATTRIBUTE.ENTITY_ID; 8 solved Join expression ambiguous
SELECT grade, COUNT( DISTINCT CASE WHEN DATE ‘2015-01-01’ >= date_column AND date_column < DATE ‘2016-01-01’ THEN customer_id END ) AS number_of_unique_customers_in_2015, COUNT( DISTINCT CASE WHEN DATE ‘2016-01-01’ >= date_column AND date_column < DATE ‘2017-01-01’ THEN customer_id END ) AS number_of_unique_customers_in_2016 FROM Customers WHERE Date_Column >= DATE ‘2015-01-01’ AND Date_Column < DATE ‘2017-01-01’ GROUP BY grade; … Read more
I’m sure there are lots of ways of doing what you want. Try this: SELECT a.* FROM FGEHF_DB.dbo.Tbl_Alotee a JOIN ( SELECT MAX(ID) AS ID FROM FGEHF_DB.dbo.Tbl_Alotee WHERE Plot_Id = ‘4117’ — or other value GROUP BY alotee_name, alotee_fname, alotee_cnic ) b ON a.ID = b.ID I think we are getting closer now. 8 solved … Read more
Your WHERE condition can be simplified like UPDATE domain_information SET company_name=”aaa” WHERE company_name=”bbb”; 2 solved i want to update table multiple row using IN statement
sp_MSforeachtable @command1=”ALTER TABLE ? ADD id int IDENTITY PRIMARY KEY CLUSTERED” The good thing is that it if it fails for some table, it doesn’t fail for all. solved How to add a primary key to all tables in SQL Server?
This will give you all the subs where the Mem and Sub are not the same. SELECT SUB FROM TABLE WHERE MEM <> SUB This will give you a distinct list of Sub’s that, at one point or another, do not have a matching MEM. SELECT DISTINCT SUB FROM TABLE WHERE MEM <> SUB EDIT: … Read more
select Status, COUNT(Status) from Count() — please be sure to use the right name of the table after From. group by Status order by COUNT(Status) desc 🙂 1 solved I am new to SQL, and trying to learn what I can through books and websites