The issue looks that the insertion should be a success but while retrieving through the QA, you see only 255 characters back. This is just a visual problem and nothing more. Just change this limitation under the Tools > Options > Results in the SSMS where you have an option to change the Maximum characters … Read more
You have to use GROUP BY command : SELECT id_unit, COUNT(*) FROM order_amount GROUP BY id_unit; Results : id_unit COUNT(*) kg 40 m3 30 pal 30 After if you want to display for each order your script will be : SELECT m.id_order, (select count(*) from order_amount m2 where m2.id_order = m.id_order and m2.id_unit=”kg”) as num_kg, … Read more
I hope this will help you. SELECT * FROM (SELECT ID,NAME,GENRE,COUNT(LAN1)+COUNT(LAN2)+COUNT(LAN3) AS KNOWN_LANG FROM YOUR_TABLE GROUP BY NAME) WHERE KNOWN_LANG >=2 solved sql query how to get who knows morethan two lanuguage
There is no ON UPDATE clause in Oracle column definitions. Oracle is complaining because it expects a closing parenthesis after DEFAULT CURRENT_TIMESTAMP. 0 solved ORACLE :missing right parenthesis [closed]
The second argument in ISNull is value that will be used when your field data is actually null. Example: IsNUll(someint, 0) the above will return someint if someint not null, otherwise, it will return 0 1 solved The isnull function requires 2 argument(s) [closed]
how to write a stored procedure for adding the values in the table when we have two or more values for the same data in stored procedure MSSQl solved how to write a stored procedure for adding the values in the table when we have two or more values for the same data in stored … Read more
You can use like Select * FROM database1.products WHERE field = ? UNION ALL SELECT * FROM database2.products field = ? UNION ALL SELECT * FROM database3.products field = ? 1 solved access multiple my sql database at a time? [closed]
Any example data would be helpful. Otherwise, here is example query: select count(*) from workers where gender=”f”; solved Find out the number of female employees in the organisation? Without using Group By [closed]
I may be the only one who finds this question quite interesting (- just not perfectly explained). Here is a SQL Fiddle Demo that shows one way of doing this using a cursor to populate the dates. The part of the script I believe you were asking for is shown below: CREATE TABLE EquipmentLog ([Item … Read more
Since the date_issue is a varchar, it would be a problem with BETWEEN. Try changing the date_issue datatype from varchar to datetime 7 solved How to get data between two dates
Try your query like this select * from images group by jy_id or you can try:- select distinct jy_id, jy_tour_book_picture from images 3 solved select sql distinct [closed]
You don’t need the % character, since the function Contains already implied that. So : select Subject from [dbo].[Email] where Contains(Subject,’t’) The % are for LIKE function select Subject from [dbo].[Email] where Subject LIKE ‘%t%’ 1 solved Search box to work like google search [closed]
I think this is what you are looking for, but as others have commented, it would be much easier if you posted what you have tried so far. Select User_ID, Seller_ID , count(case when action_type = 0 then action_type end) as Type0 , count(case when action_type = 1 then action_type end) as Type1 […] from … Read more
SQL: Column invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause [closed] solved SQL: Column invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause [closed]
Introduction SQL is a powerful language used to query and manipulate data stored in databases. It is important to understand the syntax and structure of SQL queries in order to ensure that the query is valid and produces the desired results. One common issue that can arise when writing SQL queries is the error “Column … Read more