[Solved] How to crop strings using regular expressions? [closed]

If you want to use Regex, you can use the following. “( |:).*” Example, var list= @”Summoner1 joined the lobby. Summoner2 jonied the lobby. Summoner3: Top Summoner4: ADC”; var result = list.Split(new []{Environment.NewLine},StringSplitOptions.RemoveEmptyEntries).Select(x=> Regex.Replace(x,”( |:).*”,string.Empty)); Update: Based on Comment var result = string.Join(“|”,list.Split(new []{Environment.NewLine},StringSplitOptions.RemoveEmptyEntries).Select(x=> Regex.Replace(x,”( |:).*”,string.Empty))); Output Summoner1|Summoner2|Summoner3|Summoner4 7 solved How to crop strings using … Read more

[Solved] Regular expressions doubts [closed]

m// is the match operator. // are delimiters of the regex that you are mathing. If you are using default delimiters (//), then you can skip specifying m at the beginning. If you want to use some other charaters as delimiters, for example !, then m is required: m!/some/string/with/slashes!. solved Regular expressions doubts [closed]

[Solved] How can I replace dot with comma but only for numbers in a string ? (PHP) [duplicate]

Try this one $str = “this is. an example. 15.68€”; function cleaner($matches) { return str_replace(“.” , “,” , $matches[“nrs”]); } $str = preg_replace_callback (“/(?P<nrs>[0-9]+.[0-9]+)/” , “cleaner” , $str); echo $str; I have used preg_replace_callback. The behavior of this function is almost identical to preg_replace(), except for the fact that instead of replacement parameter, one should … Read more

[Solved] PHP – How do I convert string number to number [closed]

For PHP you can do something like this: $string = “one two three four five six seven eight nine One Two Three Four Five Six Seven Eight Nine oNE tWO tHREE fOuR fIVE sIX sEVEN eIGHT nINE ONE TWO THREE FOuR FIVE SIX SEVEN EIGHT NINE”; $replace = array(0,1,2,3,4,5,6,7,8,9); $search = array(‘zero’, ‘one’, ‘two’, ‘three’, … Read more

[Solved] How can I check if an XML response contains a pattern? [closed]

In Groovy, you can use the following check (assuming text is the variable holding the string you provided in the question): if (text=~/Server returned HTTP response code: 503\b/){ println “503 code detected” } else { println “503 code not detected” } But it also seems you can just use contains: if (text.contains(‘HTTP response code: 503 … Read more

[Solved] JavaScript regex for URL [duplicate]

var myregexp =/(\b(https?|ftp|file|http):\/\/[\-A-Za-z0-9+&@#\/%?=~_|!:,.;]*[\-A-Za-z0-9+&@#\/%=~_|])/g; var str=”http://www.microsoft.com)”; //url var res=myregexp.exec(str); //execute regex query str=str.substring(0,myregexp.lastIndex)+’ ‘+str.substring(myregexp.lastIndex); I used Regex query for url from : https://stackoverflow.com/a/163684 5 solved JavaScript regex for URL [duplicate]

[Solved] How to make regex accept only uppercase and lowercase letters with accents in java? [closed]

In my opinion You get true, because regex is focused on finding letters. It would say false only, when You test string with no letters at all. Please consider changing if else statement and regex to find out if there are other symbols than letters: Pattern pattern = Pattern.compile(“[^\w]”); Matcher matcher = pattern.matcher(“testTest”); if (matcher.find()){ … Read more

[Solved] Create a custom regex

Decription Given your sample text… http://steamcommunity.com/id/rasmusvejby/ http://steamcommunity.com/profiles/76561198040893433 …this Regex… ^https?://(?:www\.)?steamcommunity\.com/(id/([^/\s]*)|profiles/([^/\s]*)) …will do the following validate the url contains steamcommunity.com matches with or without the leading www Allows http or https captures the id or profile portion of the url captures the string for the id or profile Capture Groups Group 0 gets the full string … Read more

[Solved] A regex that doesn’t match with this character sequence

This answer is to demonstrate the possibility only. Using it in production code is questionable. It is possible with Java String replaceAll function: String input = “Hi, Mr.Xyz! Your account number is :- (1234567890) , (.*) &$@%#*(….))(((“; String output = input.replaceAll(“\\G((?:[^()\\[\\]{}?+\\\\.$^*|!&@#%_\”:<>/;’`~-]|\\Q(.*)\\E)*+)([()\\[\\]{}?+\\\\.$^*|!&@#%_\”:<>/;’`~-])”, “$1\\\\$2”); Result: “Hi, Mr\.Xyz\! Your account number is \:\- \(1234567890\) , (.*) \&\$\@\%\#\*\(\.\.\.\.\)\)\(\(\(” Another … Read more