Problem with your current regex wiz r’^[0-9]{8,8}’: {8,8} minimum and maximum length you want is 8 so you can make it exact 8 like {8}, no need to have range Current regex has condition to check beginning of string but you have not defined end of string which can be defined using symbol $ which … Read more
Try this pattern \w+(?=(\s+)?sentence) Demo regex Positive Lookahead (?=(\s+)?sentence) 1st Capturing Group (\s+)? ? Quantifier — Matches between zero and one times, as many times as possible, giving back as needed (greedy) \s+ matches any whitespace character (equal to [\r\n\t\f\v ]) + Quantifier — Matches between one and unlimited times, as many times as possible, … Read more
Can try using this pattern $str=”<h3 class=”r”><a href=”https://stackoverflow.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&cad=rja&uact=8&ved=0CCUQFjAA&url=http%3A%2F%2Fstackoverflow.com%2Fquestions%2F18682352%2Fgoogle-search-results-with-php&ei=9ptsVNivF_iTsQTv-YJ4&usg=AFQjCNFdoi58ua_4oBtPM4LHybHRZVF9jQ&bvm=bv.80120444,d.cWc” onmousedown=”return rwt(this,\”\’,\’\’,\’\’,\’1\’,\’AFQjCNFdoi58ua_4oBtPM4LHybHRZVF9jQ\’,\’\’,\’0CCUQFjAA\’,\’\’,\’\’,event)” data-href=”http://stackoverflow.com/questions/18682352/google-search-results-with-php”>curl – Google search results with php – Stack Overflow</a></h3>’; $re=”/data-href=[“\”]?([^”\’ ]*)[“\’ ]/is’; preg_match($re, $str, $m); $attr_value = trim(str_replace(‘data-href=”, “‘, $m[0]), ‘”‘); echo $attr_value; Output: http://stackoverflow.com/questions/18682352/google-search-results-with-php solved regex with php pattern [closed]
A regex is not necessary: “/text/text/text/” stripPrefix “https://stackoverflow.com/” stripSuffix “https://stackoverflow.com/” or if you know they’re always there: “/text/text/text/”.tail.init 0 solved Remove symbol “/” at start and end of string
I need Numbers without Parenthesis. Use preg_match_all function with specific regex pattern: $str=”JAVA PROGRAMMING 20 (2016) JAVA PROGRAMMING 30 (2016)”; preg_match_all(“/(?!\()\b\d+\b(?!\))/”, $str, $matches); print_r($matches[0]); The output: Array ( [0] => 20 [1] => 30 ) 0 solved REGEXP only numbers withouth parenthesis
You could try the below regex. @”.*?(?= = CreateObject)|(?<=MoveObject\().*?(?=,)” OR @”\S+?(?= = CreateObject)|(?<=MoveObject\().*?(?=,)” DEMO 3 solved C# Regex questions [closed]
These are some patterns that I have written that work (in order of least efficient to most efficient in terms of “step count”): Step counts are based on this sample input: (green:bar AND black:foo) (blue:bar AND darkblue:foo) (yellow:bar AND grey:foo) (greengarden:bar AND red:foo) /(?:red|blue|green)(*SKIP)(*FAIL)|[a-z]+(?=:)/ Demo (513 steps) /\b(?!red:|blue:|green:)[a-z]+(?=:)/ Demo (372 steps) /(?<=\(|AND )(?!red:|blue:|green:)[^:]*/ Demo (319 … Read more
Supposing you want to be able to match *.swiss.ch domains and addresses: import re preg = re.compile(r'([^\.]+)\.swiss\.ch’) 5 solved Convert perl regex to python [closed]
You may use word boundaries. \b called word boundaries which matches between a word character and a non-word character. \b[a-zA-Z]\d{7}\b In js, str.match(/\b\[a-z]\d{7}\b/i)[0] DEMO 1 solved Regex to extract 1 letter followed by 7 numbers [closed]
Seems you escape brackets wrong: Try this: string regexTemplate = @”TRY MOVIE YES \[Bat2man WIN\]”; or string regexTemplate = “TRY MOVIE YES \\[Bat2man WIN\\]”; solved Regular expressions C# [closed]
Try this: public class Test { public static void main(String[] args) { String[] saveSpace = { “abcd: 1234”, “abcd : 1234”, “abcd : abcd dgdfgdf abcd dgdsfsdf”, “abcd 1234”, “asdasdas abcd abcd: sdfdsf” }; String regex = “abcd(?!\\s*\\w)(?=(?:[^:]*\\:){1}[^:]*$)”; String replace = “xyz”; for(int i = 0; i<saveSpace.length; i++) { saveSpace[i] = saveSpace[i].replaceFirst(regex, replace); System.out.println(saveSpace[i]); } … Read more
This is a “Negative Lookahead Assertion”. This code is saying “this regular expression matches only if it begins with /wiki/ and is not followed by a colon”. Consider reading through https://www.regular-expressions.info and in particular the Lookahead and Lookbehind Zero-Length Assertions. solved RegEx—-What is mean “?!:”? [duplicate]
You can use selectionEnd to control the position of cursor var target = document.querySelector(‘.creditCardText’); target.addEventListener(“keyup”, function() { var position = target.selectionStart; var prevVal = target.value; var newVal = prevVal.split(” “).join(“”); // remove spaces if (newVal.length > 0) { newVal = newVal.match(new RegExp(‘.{1,4}’, ‘g’)).join(” “); } target.value = newVal; for (var i = 0; i < … Read more
In javascript you can try to use this regexp /\+91[0-9]{10}/ 1 solved Regexp for all Indian phone numbers in 2018 [closed]
Seems to be simple: if (line.startsWith(“M”)) { String[] tokens = line.split(“\\s+”); String path = tokens[tokens.length – 1]; } solved Java Regex does not match – groups [duplicate]