[ad_1] I’m guessing that here we wish to validate these emails, for which we can use an expression similar to: ^([a-z0-9]+((?=\..+@.+\..+)[a-z0-9.]*@[a-z0-9]*\.[a-z0-9]*))$ with an i flag and we can allow more chars, if we like so. Demo RegEx Circuit jex.im visualizes regular expressions: [ad_2] solved RegEx to allow at least one dot and all character
[ad_1] You’re asking to match any number of lines of text, followed by only 1 additional newline at the end, simply: ^(.+\n)+\n(?!\n) will do what you’d like. Example here: https://regex101.com/r/Hy3buP/1 Explanation: ^ – Assert position at start of string (.+\n)+ – Match any positive number of lines of text ending in newline \n – Match … Read more
[ad_1] I believe you are looking for a regex pattern (?<!%%)(?<=%)\w+(?=%)(?!%%) That would find variables that are surrounded by a single % character on each side. Test the regex here. Java code: final Pattern pattern = Pattern.compile(“(?<!%%)(?<=%)\\w+(?=%)(?!%%)”); final Matcher matcher = pattern.matcher(input); while (matcher.find()) { System.out.println(matcher.group(0)); } Test the Java code here. UPDATE: If you … Read more