Something like this, where repetitive code is avoided and some error handling for user input: (Plus, you math was a little off, since 50,000, 100,000, and 200,000 are not being handled at all, example: (cost) < 50000 and (cost) > 50001 leaves 50,000 as a gap, since it is neither less than 50,000 or greater … Read more
Correct Code: def prime_chk(upper): print(“Prime numbers between”,0,”and”,upper,”are:”) for num in range(0,upper + 1): # prime numbers are greater than 1 if num > 1: for i in range(2,num): if (num % i) == 0: break else: print(‘Well done! You have found a prime : ‘,num ) n = int(input(‘Number to be checked:’)) prime_chk(n) solved Why … Read more
This way you can get a list of numbers from 0 to 20 x = range(0,20) This way you filter even numbers even = filter(lambda x : x % 2 == 0, x) This way you sum all the evens x = reduce(lambda x, y : x + y, even, 0) Do the proper thing … Read more
sample = “i am feeling good” output = {} output[“word”] = len(sample.split()) output[“chars”] = len(list(sample)) for elem in sample.split(): output[elem] = len(list(elem)) print(output) output: {‘word’: 4, ‘chars’: 17, ‘i’: 1, ‘am’: 2, ‘feeling’: 7, ‘good’: 4} solved A dictionary that returns number of word and each word’s lenght Python
So if I’m understanding correctly, the “Lists of List” comment pertains to nested Lists, The code you have is close to what’s needed. I believe this is what you need. print(“Enter First name, last name and Student ID number. Then press 0 to continue”) userFirst = str(input(“Enter First Here:”)) userLast = str(input(“Enter Last Name:”)) userStudent … Read more
The code of the entire function has to be indented: def _download_track(self, song_url, track_name, dir_name,metadata): if ‘.mp4’ in song_url: track_name = track_name + ‘.m4a’ else: track_name = track_name + ‘.mp3’ file_path = dir_name.replace(“.”,”_”) + “https://stackoverflow.com/” + track_name print((‘Downloading to’, file_path)) if os.path.isfile(file_path): return #print metadata #response = self._get_url_contents(song_url) #with open(file_path,’wb’) as f: #f.write(response.content) r = … Read more
You can use random.gauss to generate 6 numbers around a mean with a certain standard deviation (closeness) and as per @PatrickArtner suggestion construct the 7th one, e.g. using 3 standard devs from mean: In []: import random vals = [int(random.gauss(341/7, 3)) for _ in range(6)] vals.append(341 – sum(vals)) vals, sum(vals), sum(vals)/7 Out[]: ([47, 47, 48, … Read more
As you can see here: http://pandas.pydata.org/pandas-docs/dev/generated/pandas.DataFrame.drop_duplicates.html “subset” is not an authorized keyword for “drop_duplicates” method. I think you can use “cols” instead of “subset”. 1 solved i have this error can anyone tell me the solution [closed]
Given this dataframe: df.head() complete mid_c mid_h mid_l mid_o time 0 True 0.80936 0.80943 0.80936 0.80943 2018-01-31 09:54:10+00:00 1 True 0.80942 0.80942 0.80937 0.80937 2018-01-31 09:54:20+00:00 2 True 0.80946 0.80946 0.80946 0.80946 2018-01-31 09:54:25+00:00 3 True 0.80942 0.80942 0.80940 0.80940 2018-01-31 09:54:30+00:00 4 True 0.80944 0.80944 0.80944 0.80944 2018-01-31 09:54:35+00:00 Create a 50 moving average: … Read more
total = [] for line in lines: link = line.split(“ “)[1:] total.append(link) That should work. Let me know if that’s not what you were looking for. 1 solved storing each robots.txt value in an array
Try this: s = int(input()) sign = 1 if s < 0: sign = -1 s = s * -1 rev = str(s)[::-1] print(sign * int(rev)) solved How to reverse an integer while removing any leading zeroes?
This is a problem with your indentation. You can learn about indentation here: https://docs.python.org/2.0/ref/indentation.html and on the web. To get your code working do the following: string = “A” secret_word = “Apple” if string in secret_word: print(“Good!”) else: print(“Bad…”) 4 solved This if statement is not even working correctly
you can use datetime for this (in python 2.7) from datetime import datetime date_string = ‘20170808’ if len(date_string) == 8: datetime.strptime(date_string, ‘%Y%m%d’) else: raise ValueError(‘date need to be in format YYYYMMDD ‘) if you date is not valid than you get: a ValueError Exception ValueError: unconverted data remains: 0 2 solved validate date format in … Read more
Don’t parse this manually; Python has the urllib.parse.parse_qs function that does exactly what you want. from urllib.parse import parse_qs parse_qs(line) In Python 2 this is in the urlparse module: from urlparse import parse_qs 1 solved how to transform the string into a dict in python? [duplicate]
I am pretty sure this is all the code needed for the video, It might help as a reference. import urllib import webbrowser import time from xml.etree.ElementTree import parse u = urllib.urlopen(“http://ctabustracker.com/bustime/map/getBusesForRoute.jsp?route=22”) data = u.read() with open(“rt22.xml”, “wb”) as f: f.write(data) f.close() office_lat = 41.980262 doc = parse(“rt22.xml”) def distance(lat1, lat2): ‘Return approx miles between … Read more