[ad_1] When you make a return call within the function, the control comes back to parent (which executed the function) ignoring the code within the scope of function after return. In your case, that is why print is not getting executed by your code. Move the line containing print before return and move return to … Read more
[ad_1] Use sorted function with a custom key function:- sorted(string_name, key=order) A custom key function is supplied to customize the sort order of the function. i.e. now characters will be sorted in 23456789JQKA this order. EXAMPLE order = “23456789JQKA” print(*sorted(“KA2J32535″, key=order.index),sep=”) OUTPUT 223355JKA P.S.:- I have converted the result into a string, if you don’t … Read more
[ad_1] “Annealing”, in this sense, is an analogy to a chemical process in which temperature is reduced. Here, too, the ‘temperature’ term in the softmax is reduced, changing it gradually from a ‘soft’ sigmoid function to a ‘sharp’ argmax Try plotting a softmax function for yourself with different temperatures, you’ll see the difference… [ad_2] solved … Read more
[ad_1] You shouldn’t do total = None. NoneType cannot be used against addition. There’s an extra problem suggested by the error message: From your description you’re trying to add 3 numbers, but the return type of the builtin input() is str. So this is what you’re supposed to write: total = 0 for i in … Read more
[ad_1] You can use pandas to do that. Collect all the data into a dataframe, then just write the dataframe to file. import pandas as pd import requests import bs4 root_url=”https://www.estatesales.net” url_list=[‘https://www.estatesales.net/companies/NJ/Northern-New-Jersey’] results = pd.DataFrame() for url in url_list: response = requests.get(url) soup = bs4.BeautifulSoup(response.text, ‘html.parser’) companies = soup.find_all(‘app-company-city-view-row’) for company in companies: try: link … Read more
[ad_1] You have different indexes in the loops: for(int k = j+1; k < n; ++k) for(int l = k+1; l < n; ++l) and for k in range(i+2, n): for l in range(i+3, n): Basically, the indexes in the inner loops in your C++ code change accordingly to the loop that is one line … Read more
[ad_1] def map(func, values): rest = values[1:] if rest: yield from map(func, rest) else: yield func(values[0]) It’s a generator so you can iterate over it: for result in map(int, ‘1234’): print(result + 10) Gives: 11 12 13 14 4 [ad_2] solved how to implement map and reduce function from scratch as recursive function in python? … Read more
[ad_1] You can use a regular expression to look for _cell_length_a (or any other key), followed by some spaces, and then capture whatever comes after that until the end of that line. >>> import re >>> re.findall(r”_cell_length_a\s+([0-9.]+)”, metadatastructure) [‘2.51636378’, ‘2.51636378’] Or using a list-comprehension with splitlines, startswith and split: >>> [line.split()[-1] for line in metadatastructure.splitlines() … Read more
[ad_1] I think this is what you might be looking for! After researching how to find the data-types of variables I’ve come across this: >>> y = 2,4,6 (2,4,6) >>> print (y.__class__) <class ‘tuple’> A tuple is a data-type much like a list in that it stores seperate values, but it is indeed not a … Read more
[ad_1] This is because your listeexclure is just a string. If you want to search a string in another string, you can do following: Let’s assume you have a list like: lst = [‘a’, ‘ab’, ‘abc’, ‘bac’] filter(lambda k: ‘ab’ in k, lst) # Result will be [‘ab’, ‘abc’] So you can apply same method … Read more
[ad_1] You can use this function to check if an error exists: def checkError(Str): if ‘ERROR’ in Str: openBracket = Str.find(‘(‘)+1 closedBracket = Str.find(‘)’) status = “”.join(Str[openBracket:closedBracket]) error = “\n”.join([‘YES’,”, “.join(Str.split(‘\n\n’)[2].split(‘, ‘)[1:]),status]) return error else: return ‘No errors found.’ error = checkError(Str) print(error) Output: YES 22:17:31 Wed Feb 11, 2015 software ERROR 0 [ad_2] solved … Read more
[ad_1] You could run one apply() which will use for-loop to convert list to Series with headers – it can use enumerate to put correct number in headers. Because some rows have less participants so it puts NaN which you can later fill with empty strings. And next you can use join() to add all … Read more
[ad_1] You are trying to parse strings as numbers in hexadecimal, where each string is two characters from h. That means your string h needs to be long enough to have content for each of the substrings. For instance, if h is ‘1234’, then h[0:2] == ’12’ h[2:4] == ’34’ h[4:6] == ” Your code … Read more
[ad_1] You’re decrementing i twice: once inside the if-statement, once every time in the while loop. Hence, when the if statement evaluates to True, i will be decremented by 2 in total, and you will skip past some values of i. A quick test shows that, indeed, i == 194 is skipped: i jumps from … Read more
[ad_1] my_data=”BEAR” for i in range(len(my_data)): print(my_data[:len(my_data)-i]) #trick is here Output: BEAR BEA BE B 2 [ad_2] solved How do you print one fewer letters each time? [closed]