python

Try reducing your list. from functools import reduce def get_all_consecutives(iterable, consecutive_limit): consecutives = [] def consecutive_reducer(accumulator, next_item): if not accumulator: accumulator.append(next_item) else: if next_item – accumulator[-1] == 1: accumulator.append(next_item) else: accumulator = [next_item] if len(accumulator) == consecutive_limit: consecutives.append(accumulator) return accumulator reduce(consecutive_reducer, iterable, []) if not consecutives: return False elif len(consecutives) == 1: return consecutives[0] else: … Read more

for i in range(5): do this action Is (the Python way of saying “for each element in range(5) do this action”. range(5) can be replaced by any iterable collection. In this example the variable i is not used. We might write for i in range(5): print(i) which would print out all the values from the … Read more

If you wish to count iterations, you should use enumerate() with open(‘fin.txt’) as fin, open(‘fout.txt’, ‘w’) as fout: for i, item in enumerate(fin, 1): if i == 7: item = “string\n” fout.write(item) 2 solved Python replace line by index number

This code will terminate as the function is calld with k-1, meaning that the condition k>1 will eventually evaluate to False. Imagine recursion is like a continually growing tree and a squirrel is the interpreter. When the isort() function is called, the tree branches off and the squirrel runs to the end of that branch. … Read more

One solution with list comprehension [(a,b,c) for a in range(10) for b in range(10) for c in range(10) if a+b+c ==17] Then just convert this to strings or whatever you want. 1 solved how to generate a list of 3-digit numbers the sum of their digits equal 17?