It is going to depend on the type of data in the list. input returns everything as str. So if the list data type is float then the if statement will evaluate as True. For int data use the following: items = [variable1, variable2, variable3] choice = input(“Input variable here: “) if int(choice) not in … Read more
Alright, so first of all we need to improve the program layout , maybe call in some functions would be useful. Here is some tips to fix the program. First of all use : if username.strip() and password.strip() in line: [Use the .strip() function so it will match a word. Your program is inefficient because … Read more
I think the problem is in the part where you insert your item into the cartList. You only insert the item, not the money with it. So in the return part, it must be: if ask == ‘return’: ret = input(‘What item do you want to return?\n’) for i in cartList: if ret==i: … Or … Read more
Your start function explicitly allows access to a global variable named var. As evidenced by your error, you have no such variable defined. Please initialize the variable before the function: var = 25 def start(): global var # the rest of your function # goes here after global var 3 solved Pass variables through functions … Read more
I think the issue has to do with you’re getting your substrings. You’re slicing a multiline string, and so some of your slices will include a newline character instead of a digit. Though your multiplication code will ignore those newlines, they still matter since they change the number of actual digits in the multiplication. If … Read more
Is this what you are after? >>> d=[] >>> while(True): … s=raw_input() … if s==””:break … temp = [s] … d.append(temp) … a,b,7-6,7-6,6-3 c,d,7-4,7-6,6-2 e,f,6-4,7-6,6-2 >>> d [[‘a,b,7-6,7-6,6-3’], [‘c,d,7-4,7-6,6-2’], [‘e,f,6-4,7-6,6-2’]] This makes a list item out of the input and then appends that list to your main list d You now should be able to … Read more
It sounds from your question like you have some lines at the beginning of a script which you do not want to process each time you run the script. That particular scenario is not really something that makes a lot of sense from a scripting point of view. Scripts are read from the top down … Read more
In function unsortedSearch you have a parameter named list1, but in the body of the function it looks like you are referring to it as list. So change all of your list with list1 and your current problem will be solved: def unsortedSearch(list1, i, u): found = False pos = 0 pos2 = 0 while … Read more
def esvocal(letter): vocal =[ “a”,”e”,”i”,”o”,”u”] vocalup = [“A”,”E”,”I”,”O”,”U”] if letter in vocal and letter in vocalup: return True else: return False esvocal(“s”) esvocal(“a”) Python really cares about indentation Use in instead of == 1 solved Why it doesn’t return anything?
This is one way to approach the problem. As you can see, you can do everything with python’s builtin strings. Note that use str.lower().strip() to normalize the search terms and the menu items before comparing them. That will give more generous results and not punish users for inputting extra spaces, and is usually a good … Read more
Pretty crude way of writing the code. But see if this helps in understanding. Initially: name = [0] len(name) = 1 1st iteration name = [0, “Foo”] len(name) = 2 name[-2] = 0 if name[-2] => if 0 => False => REPEAT 2nd iteration name = [0, “Foo”, “Foo”] len(name) = 3 name[-2] = “Foo” … Read more
Your program is missing constructor and hence the error. Also do note that you are probably referring to __repr__ and not __rep__. You final code should look something like this – class Car: # In your code, this constructor was not defined and hence you were getting the error def __init__(self,name,year,model): self.name = name self.year_built … Read more
You want to traverse the dictionary, building the current key and accumulating the flat dictionary. For example: def flatten(current, key, result): if isinstance(current, dict): for k in current: new_key = “{0}.{1}”.format(key, k) if len(key) > 0 else k flatten(current[k], new_key, result) else: result[key] = current return result result = flatten(my_dict, ”, {}) Using it: print(flatten(_dict1, … Read more
The easiest way: just cut the needed part from your bytes: only_numbers = [item[18:] for item in initial_list] This expression will create a new list named only_numbers with numbers extracted from original list items. Note that this method simply omits the first 17 symbols, so, if prefix part of your initial data will change in … Read more
You don’t need the functions nor the sum or multiply variables, just put the operation in str.format(), and you were missing the last position. # def addition(num1,num2): # return num1+num2 # def multiplication(num1,num2): # return num1*num2 print(“1.addition”) print(“2.multiplication”) choice = int(input(“Enter Choice 1/2”)) num1 = float(input(“Enter First Number:”)) num2 = float(input(“Enter Second Number:”)) # sum … Read more