[ad_1] First of all, you always must include the description of what you have tried so far and what error you encountered while doing so. It is not nice to ask a question directly without showing your efforts in it. Now coming back to your question, it is actually quite very easy, what you can … Read more
[ad_1] We have some list of lists a. We want to get counts for each of the sublists, and the total of those counts. Note that the total counts will just be the sum of the counts of the sublists. from collections import Counter a = [[‘das’,’sadad’,’asdas’,’das’],[‘das’,’sadad’,’da’],[‘aaa’,’8.9′]] def count(list_of_lists): counts = [Counter(sublist) for sublist in … Read more
[ad_1] No, Python supports more collection types. You missed the tuple, the deq, the string and bytes for example. Actually the possibilities are infinite since you can make any object a collection by implementing some special methods and also you can subclass most built-in sequence times. [ad_2] solved Does Python include only 3 collection types?
[ad_1] Each version of Python installs to new folder. You’ll have to download and install the new version of Python, and install any modules that you might have done via pip in your previous version. You’ll have to take into account that some of your libraries won’t work in Python 3.6. A notable example would … Read more
[ad_1] Here’s the thing: I don’t know what exactly you are trying to accomplish, but I’m guessing that you want to know how to print in python, no? Great, then here’s how you do it: In Python 3… If you have a String, integer, float, etc. stored in variable a, then you can print by: … Read more
[ad_1] Going by the if statements: fib(0) = 0 fib(1) = 1 fib(2) = fib(2-1) + fib(2-2) = fib(1) + fib(0) = 1 + 0 = 1 fib(3) = fib(3-1) + fib(3-2) = fib(2) + fib(1) = fib(2-1) + fib(2-2) + 1 = fib(1) + fib(0) + 1 = 1 + 0 + 1 = … Read more
[ad_1] According to the tcl documentation, a ttk.Treeview widget does have commands to add and remove a tag from a node or a list of nodes. However, these methods are not provided in the official tkinter wrapper; see the Treeview class in /usr/lib/python3.8/tkinter/ttk.py. Building on the comment by @JasonYang and answer by @CoolCloud, the test … Read more
[ad_1] Use from kivy.utils import platform to get the platform the app is being run on. Then, for windows: flags, hcursor, (x,y) = win32gui.GetCursorInfo() for Linux distros, use: from Xlib import display data = display.Display().screen().root.query_pointer()._data data[“root_x”], data[“root_y”] 1 [ad_2] solved kivy capture mouse coordinates outside of window
[ad_1] I have a solution using Counter for you: import collections data = “”” ——————————— Color: red/test/base person: latest ——————————— Color: red-img-tests person: latest ——————————— Color: red-zero-tests person: latest ——————————— Color: red-replication-tests person: latest ——————————— Color: blue person: latest ——————————— Color: black/red-config-img person: 7e778bb person: 82307b2 person: 8731770 person: 7777aae person: 081178e person: c01ba8a person: … Read more
[ad_1] Notice that the names are separated by a colon(:) so add : in split() to split them and store them in multiple variables: with open(“filename.txt”) as f: for line in f : word1,word2,word3 = line.split(“:”) print(word1) print(word2) print(word3) 0 [ad_2] solved Open txt file in python
[ad_1] There are a few different components to this problem. First, how do you split the receipt into each individual company. Next you need to be able to parse the company’s ID. Finally you need to be able to parse the quantity, cost, and total cost from a line item. Splitting Receipts Your method of … Read more
[ad_1] There are no email addresses on that page. This is a typical way that is used to make contacting possible without giving an email address to the public. What happens when you press the “Send enquiry” -button is that your browser sends a HTTP POST request towards some address*, to a webserver, which then … Read more
[ad_1] Just because you asked nicely 😀 You can use the simplest for loop, with str.zfill to pad with zeroes, then add it to the ‘nam’ prefix like this: for i in range(1,11): proId = ‘nam’ + str(i).zfill(3) print(proId) # or do whatever you need with it… Output: nam001 nam002 … nam009 nam010 1 [ad_2] … Read more
[ad_1] You just have to many brackets ((df[‘Location’].str.contains(‘- Display’) & df[‘Lancaster’] == ” & df[‘Dakota’] == ‘D’ & df[‘Spitfire’] == ‘SS’ & df[‘Hurricane’] == ”)) You needed to remove a ‘)’ after each (‘- Display’) it looks like you will still have some problems with sorting through your data. But this should get you past … Read more
[ad_1] I finally found a solution, I hope someone helps from urllib.request import urlopen from bs4 import BeautifulSoup from io import BytesIO from zipfile import ZipFile file = urlopen(url).read() file = BytesIO(file) document = ZipFile(file) content = document.read(‘word/document.xml’) word_obj = BeautifulSoup(content.decode(‘utf-8’)) text_document = word_obj.findAll(‘w:t’) for t in text_document: print(t.text) [ad_2] solved Python: Extract text from … Read more