This data is taken from additional request to https://www.seloger.com/detail,json,caracteristique_bien.json?idannonce=142632059. There you will get json with whole information. UPD: url_id = re.search(r’/(\d+)\.htm’, response.url).group(1) details_url=”https://www.seloger.com/detail,json,caracteristique_bien.json?idannonce={}” # make request to url yield Request(details_url.format(url_id)) 5 solved i want to scrape this part
You can do things like this with the sympy library. http://docs.sympy.org/dev/index.html >>> from sympy import * >>> from sympy.solvers import solve >>> ca, ra = symbols(“ca ra”) >>> eq = -ra + (1.5 * (ca – (ra/2))/(1 + 0.8 * (ca – (ra/2)))) >>> print(eq) -ra + (1.5*ca – 0.75*ra)/(0.8*ca – 0.4*ra + 1) >>> … Read more
How to extract timing info like HH:MM:SS from a given list using for loop in Python without importing any module [closed] solved How to extract timing info like HH:MM:SS from a given list using for loop in Python without importing any module [closed]
you have an indentation problem : if (input(“”).lower() == “yes”): gender_set() elif name.lower()==”dev mode”: print(“dev mode activated”) gender_set() else: name_set() solved My program keeps getting an error called ‘inconsistent use of tabs and spaces’ when I add an else or elif statement [duplicate]
import random n = int(input(‘Введите кол-во столбцов матрицы: ‘)) #columns m = int(input(‘Введите кол-во строк матрицы: ‘)) #rows matrix = [[random.randrange(0, 10) for y in range(n)] for x in range(m)] for i in range(m): for j in range(n): print(matrix[i][j], end = ” “) print() max_x = 0 for i in range(m): for j in range(n): … Read more
I think you have a simple, one-line change. You get the name instead of the index, because that’s exactly what you told it to print. Instead, use this: print(‘The index of this name is ‘, index) Your original went to the extra trouble to look up the name in that location. 1 solved How to … Read more
Given a list, you can use ‘ ‘.join: s = [‘hello’,’world’] new_s=” “.join(s) Output: ‘hello world’ 1 solved How to change a split str into a normal str [duplicate]
Just use Pandas to convert your lists (income and Expenses) into Dataframes, merge them (in this case it’s basically an inner join on Year and Month) and then convert the Dataframe you get into a list of lists. df1 = pd.DataFrame(income, columns=[“Year”, “Month”, “X”]) df2 = pd.DataFrame(Expenses, columns=[“Year”, “Month”, “Y”]) joined = df1.merge(df2, on=[“Year”, “Month”]).values.tolist() … Read more
or evaluates two Boolean expressions. In your case, the statement in the bracket is evaluated first and then the in is evaluated. This leads to the if statement being interpreted as false. You do not need to use the brackets. Just do this: if ‘Null’ in y or ” in y: Now there’s a Boolean … Read more
You should give a code that actually creates the error you get, as stated from other people in the comments. Anyway, in your code, i will be a string, not a list, because you are iterating the list from split with your loop. So, maybe you should use if i == ‘because’ rather than if … Read more
Assuming your data object is a simple dict or list,all you need to do is: with open(output_path, ‘w’) as f: json.dump(data, f, sort_keys=True, indent=4) This will correctly dump to the output file. 3 solved How to fix ‘\n’ from json?
You shouldn’t try to manipulate them as strings – this will be fragile and very specific to the strings. Instead, parse the strings into dictionaries, do whatever manipulations you want, and then dump them back to JSON strings: import json s1 = ‘{“step”:”example step”, “data”:”example data”, “result”:”example result”}’ s2 = ‘{“attachments”:[ { “data”:”gsddfgdsfg…(base64) “, “filename”:”example1.txt”, … Read more
It seems you are new to the world of programming. “sys.argv” is used to take Command Line Arguments. when you run as “python sample.py”, the variable sys.argv will be a single element list i.e. [“sample.py”] len(sys.argv) is 1 in this case The Expected Working of the program is: when you run as “python sample.py fileToRead.txt”, … Read more
This can be put into one line in several ways. Without changing your code you could just remove the newline and indent: with open(‘output.txt’, ‘w’) as f: for item in winapps.list_installed(): print(item, file=f) Or just using unpacking and print formatting: with open(‘output.txt’, ‘w’) as f: print(*winapps.list_installed(), sep=”\n”, file=f) Which can also be done in one … Read more
import re FILEPATH = “./file.txt” def main(): pattern = re.compile(“‘serial_number\’\: u\'(.*?)\'”) with open(FILEPATH, ‘rU’) as f: print(pattern.findall(f.read())) if __name__ == “__main__”: main() 4 solved Extract string from text file using python [closed]