Try this query: SELECT cust_id, date FROM ( SELECT cust_id, date, row_number() OVER (partition by cust_id ORDER BY date, id ) rn FROM Transaction ) as alias WHERE rn <= 5 ORDER BY 1,2 demo: http://sqlfiddle.com/#!15/cfd2e/4 2 solved First 5 entries for a single user
In more layman’s terms, it means that for each record in Table A, you get every record from Table B (all possible combinations). TableA with 3 records and Table B with 3 records gives 9 total records in the result: TableA-1/B-1 TableA-1/B-2 TableA-1/B-3 TableA-2/B-1 TableA-2/B-2 TableA-2/B-3 TableA-3/B-1 TableA-3/B-2 TableA-3/B-3 Often used as a basis for … Read more
Your string literals should be enclosed in single quotes instead of double quotes. SELECT e.ename FROM emp e WHERE e.job = ‘MANAGER’ AND e.mgr NOT IN(SELECT empno FROM emp WHERE job = ‘MANAGER’); Also, based on your title, I wonder if this query shouldn’t be written more generically to account for any job in common? … Read more
try this: class CreatePages < ActiveRecord::Migration[5.0] def change create_table :pages do |t| t.string :name t.text :description t.text :address t.text :contact t.string :profile_image t.string :cover_image t.string :look_book t.integer :seller_id t.timestamps end end end solved Error undefined methode ‘interger’ when make migrate [closed]
This substring() expression does what you ask: substring(string, ‘\m\d+\D?*\M’) The regular expression only returns the first match, or NULL if none. \m … beginning of a word\d+ … one or more digits\D? … zero or one non-digits\M … end of word Demo: SELECT string, substring(string, ‘\d+\D?\d*\M’) FROM ( VALUES (‘FLAT 3, thanos house, nw1 6fs’) … Read more