[ad_1] You need to add the validation to the form element and set the required rule to the checkbox <form id=”myform”> <input type=”checkbox” value=”agree” name=”agree” id=”agree” /> <input type=”submit”> </form> then jQuery(function ($) { $(“#myform”).validate({ rules: { agree: { required: true } }, messages: { agree: “Please agree the terms and conditions” } }); }); … Read more
[ad_1] <?php $integers=”1,5,8,4,3″; //Convert into String $arr = explode(‘,’, $integers); // String to Array Conversation foreach ($arr as $key => $value) { $val[] = “‘”.$value.”‘”; // add your requirements here } $finalvalue = implode(‘,’, $val); // Array to string echo $finalvalue; // your final result ?> [ad_2] solved Convert integer to string
[ad_1] There are multiple issues with your current code. You fetch the first row with $row = mysqli_fetch_array($select); (line 3), but you don’t do anything with it. This means that the first result is discarded. Your while loop attempts to loop over an incorrect variable ($query is a string, not the result-object), and you’ve quoted … Read more
[ad_1] Stylish functional code: function createSeries($min, $max, $interval, $connector) { return array_map( function ($num) use ($interval, $connector) { return implode(‘ ‘, array($num, $connector, $num + $interval)); }, range($min, $max – $interval, $interval) ); } However, the most efficient way seems to be: function createSeries($min, $max, $interval, $connector) { $series = array(); for ($i = $min; … Read more
[ad_1] Try this script: <?php $aFilters[‘AgentName’]; $i = 0; foreach($agentsName as $ar) { echo “<option value=”$ar->id”>$ar->first_name$ar->last_name</option>”; $i++; } ?> <select <?php if ($i > 0) { echo ” disabled “} ?> name=”AgentName” id=’selAgentName’> <option value=””>Select Agent</option> </select> remove drop down script: <?php $aFilters[‘AgentName’]; $i = 0; foreach($agentsName as $ar) { $i++; if ($i>1) { echo … Read more
[ad_1] Change your code following way- <?php $date2=date(‘Y’, strtotime(‘+1 Years’)); for($i=date(‘Y’); $i<$date2+5;$i++){ echo ‘<option>’.$i.’-‘.($i+1).'</option>’; } ?> [ad_2] solved PHP How to generate School Year?
[ad_1] No, it’s not ok – you should define the variables you use. If it’s not defined, it might be defined by, say, some other php script (assuming you have multiple in use, which is a common case). The way to clear up the error is to define variables used. 2 [ad_2] solved error_reporting(E_ALL); Says … Read more
[ad_1] What value will var_dump show that echo will not show? You cannot echo an array if you do so it will just print data type not the data, you can use var_dump to print complete structure and data of an array. $array = array(1,2,3); echo $array; //<—-only print the data type var_dump($array) //<—–print the … Read more
[ad_1] One option to your expected output is to create a indexed array with the associative array below it. This will create this kind of array: array(4) { [0]=> array(1) { [203]=> int(1) } [1]=> array(1) { [204]=> int(2) } [2]=> array(1) { [203]=> int(2) } [3]=> array(1) { [205]=> int(1) } } This is … Read more
[ad_1] What’s Wrong You’re trying to use a “variable variable” by building a variable name from two pieces, split and $i. This is not usually the best way to do things, and you’re doing it incorrectly. $split($i) doesn’t mean “the variable named ‘split and the value of $i.’” It means, “take a variable named $split, … Read more
[ad_1] Missing quotes for user_name : $user = “SELECT COUNT (*) FROM user_details WHERE user_name=”$username””; [ad_2] solved After connecting to database, select query doesn’t output anything [closed]
[ad_1] Try this once!! function loadpage(){ //only for one textarea var text = document.getElementByTagName(“textarea”).value; $.ajax({ type: ‘POST’, url: ‘lib/ajax.php’, data: {‘data1’: text}, success: function(res){ $(“#inneroutput”).html(res); } }); [ad_2] solved how to send data from js to php? [closed]
[ad_1] $values = explode(PHP_EOL, $row); foreach($values AS $data){ echo ‘<li>’.$data.'</li>’; } You should normalize this data, it’s not the right way to store it. 0 [ad_2] solved PHP/MySQL adding before and after every row
[ad_1] A lot of it depends on how your theme is set up, but here’s a general overview: 1. Ensure that you are using the body_class() function Check you theme’s header.php and ensure the body tag looks something like: <body <?php body_class(); ?>> This will automatically add a bunch of classes to your body tag, … Read more
[ad_1] Following pattern extracts it all. @\[(img|thumb)\](.+?)\[/\\1@ Ideone [ad_2] solved How to extract URLs from within a string containing markup?