[Solved] mysql return date by top position

Consider the following… DROP TABLE IF EXISTS my_table; CREATE TABLE my_table (id INT NOT NULL AUTO_INCREMENT PRIMARY KEY ,userid INT NOT NULL ,date DATE NOT NULL ,score INT NOT NULL ,UNIQUE(userid,date) ); INSERT INTO my_table (userid,date,score) VALUES (1,’2017-09-30′,1), (1,’2017-10-01′,1), (2,’2017-10-01′,2), (1,’2017-10-02′,2), (2,’2017-10-02′,2), (3,’2017-10-02′,1); SELECT x.* , COUNT(DISTINCT y.score) rank FROM my_table x JOIN my_table y … Read more

[Solved] How to crete this type of array through using of Loop?

$d1 = array(); for($i=0;$i<10;$i++){ array_push($data, array(‘title’ => $mytest[$i], ‘heading’ => ‘My Heading’, ‘message’ => $my[$i],) ); } Now $data[‘mytest’] = $d1 Here , we are basically pushing the sub-arrays in main array and then will assign the array created to mytest solved How to crete this type of array through using of Loop?

[Solved] Php Newbie, echo not working?

I suppose that you have forgotten to let the filename end with .php. So everything between the <(?php) and the (?)> is interpreted as a html tag and not visible. See your raw html output, then you may notice what’s going on. 1 solved Php Newbie, echo not working?

[Solved] TypeError: array[i] is undefined

You are not allowed to put a PHP array directly to JavaScript. Please try to json_encode it: onclick=’mostrarModal(“.$idboton.”,”.json_encode($arraynombres).”);’ Regarding your JavaScript I would suggest to directly use eventos instead of copying the elements to array: for(var i =0; i < eventos.length;i++) { acumuladordenombres = acumuladordenombres +’ ‘+ eventos[i][0]; } solved TypeError: array[i] is undefined

[Solved] Login form: no matter what it displays the message of “Username/Password combination incorrect” [closed]

$sql = “SELECT * FROM users WHERE username=”$username” and password = ‘$password'” This works for me do not know why it does not for you guessing its your database setup rember this can be “hacked” solved Login form: no matter what it displays the message of “Username/Password combination incorrect” [closed]

[Solved] Always redirect me to admin.php [closed]

Sending something to the browser with echo”Your Login Name or Password is invalid”; does not make any sense before calling header(“location: invalid.html”); because you can’t send header information after you send payload. You should remove the echo-Line or the redirect will not work. In addition to that, session_register() is deprecated by PHP 5.3 and got … Read more

[Solved] need help for a function in php

The issue with your script is <?php> However, you can make it shorter by, using range() to create an array of all integers from 0 to 500, then array_sum() to calculate the sum, then subtract 42. echo array_sum( range(0,500) ) – 42; https://eval.in/518979 0 solved need help for a function in php

[Solved] How to add pagination in php

You need to first count the number of rows in your present query: $numrows = $s->rowCount(); and need to place a vaiable for results per page say $resultsPerPage: $resultsPerPage=10; Then the page you are currenty in: $offset=$_REQUEST[‘offset’]; Then you need to run the below code : $limit=$resultsPerPage; $PHP_SELF=$_SERVER[‘PHP_SELF’]; if($numrows >= 1) { // determine if … Read more

[Solved] PHP Notice: Undefined offset

The error Notice: Undefined offset is in essence saying that you have attempted to reference a value of an array that does not exist. Reviewing your code, there are two possible instances where this can happen, first $_POST[‘checkbox’] and second $checked[$i]. You can resolve this error by something like this if (isset ($_POST[‘submit’])) { $checked … Read more

[Solved] How to display like this format in PHP

I think giving some more information about what you try to archieve and what you already have would be better for the response. Could you maybe tell if you already getting the data, how you are getting the data(format). Its simple if you are using a framework like laravel, in controller fetch the data from … Read more

[Solved] I need to restrict age for below 18 years age from the current date in Php

Try this.. <script> function getAge() { var dateString = document.getElementById(“date”).value; if(dateString !=””) { var today = new Date(); var birthDate = new Date(dateString); var age = today.getFullYear() – birthDate.getFullYear(); var m = today.getMonth() – birthDate.getMonth(); var da = today.getDate() – birthDate.getDate(); if (m < 0 || (m === 0 && today.getDate() < birthDate.getDate())) { age–; … Read more

[Solved] Why this don’t work? [closed]

Little change. Issue in execute. You are passing blank array in this. So you have to check first if array containing value or not function db_toplu_veri_oku($query, $execute = array() , $binds = array(),$debug = false) { global $db; $query = $db->prepare($query); foreach($binds as $bind) { $query->bindValue($bind[0], $bind[1], $bind[2]); } if(count($execute)) //<———–Add this condition $select = … Read more