[ad_1] The session_is_registered is deprecated, just use isset to check: if(!isset($_SESSION[‘admin’])){ And for header already sent notice, you should make sure there is no output before session_start() and any head() function. Your case is most caused by the deprecated notice if your display_errors config is on. 1 [ad_2] solved php session function says deprecated
[ad_1] maybe something like this: var totalFields = <?=$total_fields?>; var currentFields = 0; var addMode = document.getElementById(‘addMore’); var form = docuement.getElementsByTagName(‘form’)[0]; addMore.onclick = function() { if (currentFields >= totalFields) { return false; } var newField = document.createElement(‘input’); newField.setAttribute(‘type’, ‘file’); newField.setAttribute(‘name’, ‘file’+currentFields); form.appendChild(newField); currentFields++ } and then <? foreach ($_FILES as $file) { // i guess … Read more
[ad_1] <?php $i=1; while ( $loop->have_posts() ) : $loop->the_post(); ?> <!– individual panel –> <div class=”panel panel-default”> <div class=”panel-heading”> <h4 class=”panel-title”> <a data-toggle=”collapse” data-parent=”#faqs” href=”#<?php the_ID(); ?>”> <?php the_title(); ?> </a> </h4> </div> <div id=”<?php the_ID(); ?>” class=”panel-collapse collapse <?php if ($i==1) { echo ‘in’; } ?>”> <div class=”panel-body”> <?php the_field(‘answer’); ?> </div> </div> </div> … Read more
[ad_1] Using JQuery UI Autocomplete : Try this code Script $(function() { var availableTags = [ “ActionScript”, “AppleScript”, “Asp”, “BASIC”, “C”, “C++”, “Clojure”, “COBOL”, “ColdFusion”, “Erlang”, “Fortran”, “Groovy”, “Haskell”, “Java”, “JavaScript”, “Lisp”, “Perl”, “PHP”, “Python”, “Ruby”, “Scala”, “Scheme” ]; function split( val ) { return val.split( /,\s*/ ); } function extractLast( term ) { return … Read more
[ad_1] In the code you’ve provided I can see two issues: you are overwriting the data in $result in the second call to mysql_query() you are also looking for the current date (NOW()) to be between your constraints. Assuming that you’re using a DATE or DATETIME column in MySQL rather than a VARCHAR you can … Read more
[ad_1] You have the following in your code: $name = $_POST[‘$name’]; $email = $_POST[‘$email’]; $dob = $_POST[‘$dob’]; You’re basically trying to access undefined indexes. Remove the extra $ from the key names: $name = $_POST[‘name’]; $email = $_POST[’email’]; $dob = $_POST[‘dob’]; Then, further below, you have some conditions like this: if(condition == true) { continue; … Read more
[ad_1] This condition will fail when it is 0: !empty ($_POST[‘interest’]) emtpy() will be true, so !empty() will be false. All posted values are strings, so to test for a 0 value, you could use for example $_POST[‘interest’] === ‘0’. However, that would of course fail for a string like ‘0.00’ 2 [ad_2] solved incorrect … Read more
[ad_1] The solution is the data cutting between {}. Try this: $result = preg_replace(“#\{img:(.*)\}#U”,'<img src=\’$1\’ style=\’width:100%\’ />’,$content); 0 [ad_2] solved Match content between parenthesis and get the url and change it to img tag using RegExp PHP [duplicate]
[ad_1] it should be like this way : function mdp() { var str = “<?php echo ‘coucou’;?>”; alert(str); } 2 [ad_2] solved Why PHP in script don’t work
[ad_1] You are using $_POST[‘SAVE’] where as in form it is “save” change your $_POST to $_POST[‘save’]; 5 [ad_2] solved PHP – I cannot update my database [closed]
[ad_1] There is one problem your not setting value and its empty. By which the values you select wont be added or updated to your database. The second is you have not given the name to your select dropdown by which even if you select the values it wont be posted to your action. <form … Read more
[ad_1] $query = $this->db->query(“SELECT * FROM table-one JOIN table-two ON table-1-id = table-2-id”); return $query->result(); Note:- JOIN and ON are keywords to get data of both tables AND table-one and table-2 are your required tables AND table-one-id and table-two-id are the column names of both tables for the join [ad_2] solved How to Join Two … Read more
[ad_1] Typically this is done via rewrite rules (i.e. mod_rewrite on Apache). So for Apache that might involve modifying the conf file for the host, or applying the following in an .htaccess file in the web root (assuming the host config allows for such override) RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^someapp/(.*)$ … Read more
[ad_1] Which parameters did you use in your request? You can take this as an example: https://en.wikipedia.org/w/api.php?action=opensearch&search=PHP&limit=1&format=json You said there that you want only the first definition, so you can put limit=1. The response is in json. 1 [ad_2] solved Parsing definitions in json format from Wikipedia API in php [closed]
[ad_1] <?php function so56917978_upload_callback() { //Register variables $adddate = $_POST[‘adddate’]; $addcontact = $_POST[‘addcontact’]; $adda = $_POST[‘adda’]; $addb = $_POST[‘addb’]; $addincome = $_POST[‘addincome’]; $addpayment = $_POST[‘adddate’]; $addsubbie = $_POST[‘addsubbie’]; $addcust = $POST[‘addcust’]; //connect with Database $host_name=”zzz.hosting-data.io”; $database=”zzz”; $user_name=”zysql_connect($host_name, $user_name, $password); if(!$connect) { die(“Not Connected To Server’); } //Connection to database if(!mysql_select_db($connect, $database)) { echo ‘Database Not … Read more