[Solved] add column in dataframe
I think need: df[‘Id’] = [‘Author-Id-{:03d}’.format(x) for x in range(1, 151)] 0 solved add column in dataframe
I think need: df[‘Id’] = [‘Author-Id-{:03d}’.format(x) for x in range(1, 151)] 0 solved add column in dataframe
.any(1) is the same as .any(axis=1), which means look row-wise instead of per column. With this sample dataframe: x1 x2 x3 0 1 1 0 1 0 0 0 2 1 0 0 See the different outcomes: import pandas as pd df = pd.read_csv(‘bool.csv’) print(df.any()) >>> x1 True x2 True x3 False dtype: bool So … Read more
How can I extract a string from a text field that matches with a “value” in my Dictionary and return the dict’s key into a new column in the Output? [closed] solved How can I extract a string from a text field that matches with a “value” in my Dictionary and return the dict’s key … Read more
Given the following dataframe: df = pd.DataFrame({ ‘B’: [‘a’, ‘a’, ‘c’, ‘d’, ‘a’], ‘C’: [‘aa’, ‘bb’, ”, ‘dd’, ‘do’], }) B C 0 a aa 1 a bb 2 c cb 3 d dd 4 a do value_counts method counts the occurrences of all values in column ‘B‘: df.B.value_counts() a 3 d 1 c 1 … Read more
Option 1 The simplest and most direct – use the str accessor. v = df.ID.astype(str) df[‘Year’], df[‘ID’] = v.str[:4], v.str[4:] df DateTime Junction Vehicles ID Year 0 2015-11-01 00:00:00 1 15 1101001 2015 1 2015-11-01 01:00:00 1 13 1101011 2015 2 2015-11-01 02:00:00 1 10 1101021 2015 3 2015-11-01 03:00:00 1 7 1101031 2015 4 … Read more
How can I count the number of times a string occurs in a pandas column based on categories of strings in another data frame? [closed] solved How can I count the number of times a string occurs in a pandas column based on categories of strings in another data frame? [closed]
import itertools import pandas as pd dfs_in_list = [df1, df2, df3, df4, df5] combinations = [] for length in range(2, len(dfs_in_list)): combinations.extend(list(itertools.combinations(dfs_in_list, length))) for c in combinations: pd.concat(c, axis=1) 0 solved Combinations of DataFrames from list
A simple merge using df.merge does this: df1.merge(df2, on=[‘A’]) A B_x B_y 0 a 1 3 1 a 1 4 2 a 2 3 3 a 2 4 4 b 1 3 5 b 2 3 2 solved Merging two dataframes in python pandas [duplicate]
You can try this code below: import pandas as pd df = pd.read_csv(r’your csv file path’) res = df[(df.apply(lambda s: s.eq(‘CA’).any(), axis=1))] print(res) 0 solved How to use python pandas to find a specific string in various rows
I appreciate being downvoted without given reasons why my question deserves a downvote. I was able to figure it out on my own though. Hopefully, this may answer other people’s questions in the future. import csv import pandas as pd temp = [] #initialize array with open(‘C:/Users/sword/Anaconda3/envs/exceltest/RF_SubjP02_Free_STATIC_TR01.csv’, ‘r’) as csvfile: csvreader = csv.reader(csvfile, delimiter=”,”) for … Read more
You can simply use the csv module from the standard library: import csv with open(‘__.csv’, ‘r’, newline=””) as f: reader = csv.reader(f) _ , *header = next(reader) d = {} for k, *row in reader: d[k] = dict(zip(header, row)) print(d) {‘reviews’: {‘JOURNAL_IMPACT_FACTOR’: 27.324, ‘IMPACT_FACTOR_LABEL’: ‘Highest’, ‘IMPACT_FACTOR_WEIGHT’: 37.62548387}, ‘hairdoos’: {‘JOURNAL_IMPACT_FACTOR’: 40.0, ‘IMPACT_FACTOR_LABEL’: ‘middle’, ‘IMPACT_FACTOR_WEIGHT’: 50.0}, ‘skidoos’: … Read more
You can use groupby and join to create the expected output. One way is to create a column to_join from the columns Tri_gram_sents and Value, and then agg this column: df[‘to_join’] = df[‘Tri_gram_sents’] + ‘ ‘ + df[‘Value’].astype(str) ser_output = df.groupby(‘sentence’)[‘to_join’].agg(‘ ‘.join) Or you can do everything in one line without create the column with … Read more
Do you really mean a swarmplot with several hundred thousand points? Besides it’s gonna take forever, it’s nonsense. Try with the first 1000 and see what kind of mess you get. Then use a boxplot or a violinplot instead. Try to understand your tools before using them. From the docstring: […] it does not scale … Read more
When you merge your dataframes, you are doing a join on values that are not unique. When you are joining all these dataframes together, you are getting many matches. As you add more and more currencies you are getting something similar to a Cartesian product rather than a join. In the snippet below, I added … Read more
If you have it as datetimeobject: datos[‘day’] = dados[‘time’].dt.date datos[‘time’] = dados[‘time’].dt.time If you have it as string object: datos[‘day’] = dados[‘time’].str[:11] datos[‘time’] = dados[‘time’].str[11:] Or data[[‘day’, ‘time’]] = data[‘time’].str.split(‘ ‘).apply(pd.Series) data[[‘day’, ‘time’]] = data[‘time’].str.split(‘ ‘, expand=True) Or using regex data[[‘day’, ‘time’]] = data[‘time’].str.extract(‘(.*) (.*)’) To convert it to string: datos[‘time’] = dados[‘time’].astype(str) It is … Read more