Just another try on the code base of the question , #include<iostream> #include<string.h> using namespace std; int main() { string pass; string enc=”akdhigfohre”; string x = “”; string y = “”; cout<<“Enter new password: “; cin>>pass; cout<<“\n\nYour New Password is:” << pass<<endl; for(size_t i = 0; i < pass.size(); ++i){ x += pass.at(i)^enc.at(i%enc.size()); } cout<<“\n\nEncrypted … Read more
Given that 98% of the time is spent in that function, I rewrote your “get a number” function: int Ten_To_One_Million_Ten(void) { unsigned Number = (((unsigned)rand() << 5) + (unsigned)rand()%32) % 1000000 + 10; assert(Number >= 10 && Number <= 1000010); return Number; } Now, on my machine, using clang++ (Version 3.7 from about 4 weeks … Read more
You probably meant to write a * (a//b). Multiplication happens before division, since it’s on the left and has same priority. solved a * a//b doesn’t work properly in Python (// Operator)
!ok is the same as ok == 0. Remember that in C, any non-zero scalar value in a Boolean context means “true” while zero means “false”. It’s a common C idiom to write !foo instead of foo == 0. It works for pointers as well: FILE *foo = fopen( “some_file”, “r” ); if ( !foo … Read more
As the comments and answer suggest, this is a bitwise operator. Bitwise operators treat their operands as groups of bits when they operate on them. A bitwise and will, as I’m sure you could guess, and two bits, so a truth table would look like: A | B | A & B —|—|—— 0 | … Read more