You could use two different database handles. As a general rule mixing MySQL and MySQLi in the same code is a bad idea and the MySQL code will probably get deprecated in a few years. 1 solved Is it Possible to have two database connection in a single page in php? [closed]
There are a few things you will need to know to be able to do this. Firstly the security bit… Basically you want to never trust data that is submitted to your application. When accepting data for use in a MySQL statement, you could use PHP’s built in escape functions for MySQL. ref: http://php.net/manual/en/mysqli.real-escape-string.php You … Read more
MySQL extension was deprecated in PHP 5.5.0, and it was removed in PHP 7.0.0. Instead, the MySQLi or PDO_MySQL extension should be used. Use MySQLi-connect insted of MySQL_connect as well as instead of mysql_select_db use mysqli_select_db EDIT 01 in mysqli_connect you can select database too $link = mysqli_connect(“127.0.0.1”, “my_user”, “my_password”, “my_db”); 6 solved How to … Read more
You’re doing well, just apply a filtering function to each row you recieve: // SO UPDATE THE QUERY TO ONLY PULL THAT SHOW’S DOGS $query = “SELECT * FROM result WHERE first IS NOT NULL”; $result = mysqli_query($connection, $query); if (!$result) { trigger_error(“Query Failed! SQL: $query – Error: “. mysqli_error($connection), E_USER_ERROR); } else { // … Read more
It seems like you’re trying to set the value in a column called “january” to zero for all rows. Is that really what you want to do? If so then try to remove the quotes around “$date”. It shouldn’t be quoted because it’s a column name. Also, note that if $date would come from a … Read more
Warning: mysqli_stmt::bind_param(): Number of variables doesn’t match number of parameters in prepared statement [duplicate] solved Warning: mysqli_stmt::bind_param(): Number of variables doesn’t match number of parameters in prepared statement [duplicate]
The error says ” Wrong parameter count “ so you passing the wrong number of parameters. http://php.net/manual/en/mysqli-stmt.bind-param.php show you need at least 2 try this if(!($stmt->bind_param(‘s’,$_POST[‘addArtistTextField’]))) Your instructs ssii means option 1 and 2 are strings 3 and 4 are ints 2 solved Warning: Wrong parameter count for mysqli_stmt::bind_param() [closed]
first, please dont use ‘date’ as your field name, lets say you rename it as news_date. How about this? <?php $query = mysql_query (“SELECT * FROM yourtable ORDER BY id DESC LIMIT 3”); $number = 1; while ($result = mysql_fetch_array($query)) { $id = $result[‘id’]; $title = $result[‘title’]; $news_date = $result[‘news_date’]; $post = $result[‘post’]; ?> <div … Read more
use pre tag <pre> <?php print_r($data); ?> </pre> or <?php echo ‘<pre>’; print_r($data); echo ‘</pre>’; ?> 1 solved Retrieve json from mysql using php
Unless there’s more to the picture, why not just query everything, ordered by section, to have the A-Z: SELECT * FROM Main_Section ORDER BY section … and then process the results with one loop, which could look something like this: $sections = $connect->query(“SELECT * FROM Main_Section ORDER BY section”); while ($row = $sections->fetch_array()) { echo … Read more
Found this to be an issue with SELinux that is not allowing httpd network connections. Executing: setsebool -P httpd_can_network_connect=1 Solved the problem. solved PHP not connecting to Remote MySQL [duplicate]
Code should be <?php #FileName = “Connection_php_mysql.htm” #Type = “MYSQL” #HTTP = “true” $hostname_Main_DB = “localhost”; $database_Main_DB = “mydb”; $username_Main_DB = “root”; $password_Main_DB = “”; $con = mysqli_connect($hostname_Main_DB,$username_Main_DB,$password_Main_DB, $database_Main_DB) or die ( “Failed to connect to MySQL: ” . mysqli_connect_errno()); $db=mysqli_select_db($database_Main_DB,$con) or die( “Failed to connect to MySQL: “.mysqli_connect_errno()); ?> You should remove “new”. For … Read more
Please try this: $result = mysqli_query($con,”SELECT * FROM lista”);; ?> <html> <table border=”1″> <?php if (mysqli_num_rows($result) > 0) { // output data of each row while($row = mysqli_fetch_assoc($result)) { ?> <tr> <td><?php echo $row[‘nazwiskoimie’]?></td> </tr> <?php } } ?> </table> </html> 3 solved Mysql and php w/ html database issue
He created the Order.php to keep the class elements external from the main code. This is cleaner code and easier to maintain. and how can i store the Refrence of $order with the Object? You are already storing this in $newOrders? Added comments to each line for main.php <?php // these includes are just bringing … Read more
PDO might be a better way to go. It can provide for prepared statements which can remove instances of SQL injection attacks Have a look at the manual for PHP’s PDO here solved Mysqli login – Am i protected against Sql injection with this code? [closed]