The problem is that you are getting multiple rows back and storing your id in one variable that gets overwritten every loop. I would recommend you create a class (if u are going the OO way) and add that to the list instead $sortedData = []; class Fotograf { public $Id; public $Firma; } // … Read more
Since I raised the idea, I suppose I should illustrate the use of prepared statements. Using mysqli one would proceed as follows (assuming $connection has been successfully initialized): // The indentation here is purely a matter of personal preference $query = ‘SELECT business_name, vd.ID_Vendor, res.ID_RestaurantEstablishment FROM restaurant res INNER JOIN vendor_data vd ON vd.ID_Vendor = … Read more
Because it also includes an array filled with columns’s positions (i.e: 0, 1, 2, 3 and id, username, password, email). Both id and 0 hold the same data. If you only want the string indexes, you can use mysqli_fetch_assoc (http://php.net/mysqli_fetch_assoc) 0 solved Why does mysqli_fetch_array() return array double the size? [closed]
<?php $sql = new mysqli(‘127.0.0.1′,’root’,’Qwert12345′,’plot_io_db’); //echo $sql->query(‘Select * From players’); ?> It will work. Just remove port from localhost (127.0.0.1) 0 solved PHP cant connect to MySql (MySqli)
To achieve this you will need ajax, you have two options on the username field you can have an onblur event, then call a function that will check the username in the database using the onblur event. <input name=”username” type=”text” id=”username” onBlur=”checkAvailability()”> The onblur event occurs when an object loses focus. The onblur event is … Read more
Try this query : select OrderId, CustomerName, sum(ProductAmount*Price) as Total from Order O inner join OrderDetail OD on O.Id = OD.Id group by OrderID, CustomerName solved Generate payment from more than 1 columns in SQL