[ad_1] you have to call db_connection() before your are able to use if (connect.State == ConnectionState.Open) otherwise connect is null and has no State property 1 [ad_2] solved Object reference, c# [duplicate]
[ad_1] Since I raised the idea, I suppose I should illustrate the use of prepared statements. Using mysqli one would proceed as follows (assuming $connection has been successfully initialized): // The indentation here is purely a matter of personal preference $query = ‘SELECT business_name, vd.ID_Vendor, res.ID_RestaurantEstablishment FROM restaurant res INNER JOIN vendor_data vd ON vd.ID_Vendor … Read more
[ad_1] You need to use OR AND (Genre like ‘%$genre%’ OR Genre2 ‘%$genre%’ OR Genre3 ‘%$genre%’); 7 [ad_2] solved how can I do it? (3 columns) 1 like [duplicate]
[ad_1] delete t1 from some_table t1 join some_table t2 on t2.a3 = t1.a3 and t2.a4 > t1.a4; Demo: http://rextester.com/RERGD32491 This will only keep rows with the highest value in A4 per A3. It’s possible that two rows with the same value in A3 have the same highest value in A4. Since you didn’t specify what … Read more
[ad_1] Try this, this will do. SELECT a.id, a.close FROM ( SELECT id, close FROM `orders` ORDER BY close DESC ) AS a GROUP BY DATE(a.close) ORDER BY a.id ASC; 1 [ad_2] solved MYSQL request | GROUP BY DAY [closed]
[ad_1] Maybe something like this? SELECT p.title, p.model_no, b.brand_name, c.category_title, s.specification_title FROM tbl_product AS p LEFT JOIN tbl_brand AS b ON b.id = p.brand_id LEFT JOIN tbl_category AS c ON c.id = p.category_id LEFT JOIN tbl_product_specification AS s ON s.product_id = p.id WHERE p.title LIKE ‘keyword’ OR p.model_no LIKE ‘keyword’ OR b.brand_name LIKE ‘keyword’ OR … Read more
[ad_1] Because it also includes an array filled with columns’s positions (i.e: 0, 1, 2, 3 and id, username, password, email). Both id and 0 hold the same data. If you only want the string indexes, you can use mysqli_fetch_assoc (http://php.net/mysqli_fetch_assoc) 0 [ad_2] solved Why does mysqli_fetch_array() return array double the size? [closed]
[ad_1] PHP is a programming language that’s primarily used for server-side web programming. MySQL is a relational database. The reasons you see them used together are as follows: Both are free and open-source Both are widely available on most web hosts (even shared hosting providers) PHP is used to create dynamic web pages, while MySQL … Read more
[ad_1] It would be something like: delete t from loginsystem t where premium = ‘1 DAY’ and created_at < now() – interval 1 day; [ad_2] solved MySQL: Delete rows that contain a specific parameter and are older then a day [closed]
[ad_1] I think it is better to use a database that is not used by anything else but whatever uses the data (as it is a lot of text data and may slow down SQL queries) and create seperate tables for each category of data. Ad@m [ad_2] solved Best way to store large data in … Read more
[ad_1] <?php $sql = new mysqli(‘127.0.0.1′,’root’,’Qwert12345′,’plot_io_db’); //echo $sql->query(‘Select * From players’); ?> It will work. Just remove port from localhost (127.0.0.1) 0 [ad_2] solved PHP cant connect to MySql (MySqli)
[ad_1] Use mysql_fetch_row, then you can use $row_data[0] etc. while ($row_data = mysql_fetch_row($res_data)) { $html .= ‘<tr>’; for($i = 0; $i < count($row_data); $i++) { $html .='<td>’.$row_data[$i].'</td>’; } $html .= ‘</tr>’; } Please note that you should not combine this with SELECT * as any changes to the column order would break your code. 8 … Read more
[ad_1] using IN operator should NOT have performance issues. If you insist NOT using IN operator, replace your query with: Select col1,col2,col3 from table1 where col4=1 OR col4=2 OR col4=3 OR col4=4; [ad_2] solved In operator alternative in mysql
[ad_1] In your query here: UPDATE users_table SET ‘date_last_inlog’ = NOW() WHERE user_name=”$user_name” Try removing the quotes around date_last_inlog or changing them to backticks: UPDATE users_table SET date_last_inlog = NOW() WHERE user_name=”$user_name” Also, don’t use the mysql_* functions, use mysqli or PDO instead. Your code is vulnerable to SQL Injection. 9 [ad_2] solved I can’t … Read more
[ad_1] Try below: Select * FROM YourTable WHERE ID BETWEEN 100 AND 140 OR Select * FROM YourTable WHERE ID > 100 AND ID < 140 0 [ad_2] solved Sql query to select ID from 100 to 140 [duplicate]