The distinct keyword is supposed to be outside like below, SELECT DISTINCT column1, column2, … FROM table_name; ? Also, you are trying to sum few things, It should be something like below, SELECT UID, COUNT(UID) AS TOTAL, SUM(CASE WHEN SYSTEM = ‘Android’ THEN 1 ELSE 0 END) AS A, SUM(CASE WHEN SYSTEM = ‘IOS’ THEN … Read more
Just Add KEY in PRIMARY like PRIMARY KEY, you have missed the SQL syntax. CREATE TABLE users (id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY, firstname VARCHAR(30) NOT NULL, lastname VARCHAR(30) NOT NULL, email VARCHAR(30) NOT NULL); solved Where is the error in this sql statement?
Try to connect with following mysql_connect(“localhost”,”root”, ”) or die(mysql_error()) MYSQL is Deprecated So please use mysqli 5 solved mysql Access denied for user ”@’localhost’ to database ” [closed]
Move your table rows inside the while loop and your title line before the loop and then you will see all the data and not just the last line $sql = $wpdb->prepare(“select i.siteID , i.siteNAME, i.equipmentTYPE, c.latitude , c.longitude, c.height , o.ownerNAME , o.ownerCONTACT, x.companyNAME, y.subcontractorCOMPANY , y.subcontractorNAME, y.subcontractorCONTACT from site_info i LEFT JOIN owner_info … Read more
using laravel database builder: $weight = DB::table(‘weight’)->where(‘grammage’, ‘150’)->first(); echo $weight->price; https://laravel.com/docs/5.5/queries#selects solved sql select in table grammage
Without a MCVE and actual requirements on which image you want from the images table and a better understanding of why you need a left join when your where clause makes it behave like an inner… and why the where clause is so complex… …I’m really unsure what the question is after… Here’s a shot… … Read more
You can use the where_in method as a shortcut to multiple or-statements for the same column: $available_ids = [1, 2, 3]; $this->db->where_in(‘id’, $available_ids); // WHERE id IN (1, 2, 3) If you were looking to check multiple columns (the name is ‘Adam’ or the title is ‘Grand Poobah’ or the status is ‘Active’), you can … Read more
Below is the modified code with Prepared Statement. First step is to connect to the database. To do that, we need to define the access details. // Define Database Credentials $servername = “localhost”; //Server Name $username = “KyleHulse”; //Username to the DB $password = “(my password)”; //Password to the DB $dbname = “csdb1082”; //Name of … Read more
Your description of what you want for the desired the result is not exactly clear but it seems like you can use the following to get the result. This get the total number of rows per username on each of the previous 5 days (based on the max date) as well as the total number … Read more
Wrap the result in another table. echo “<table>”; $count = 0; $num_columns = 2; // or 3 while ($rc = mysql_fetch_array($results_course)) { if ($count++ % $num_columns == 0) { echo “<tr>”; } echo “<td>”; // previous table code here echo “</td>”; if ($count % $num_columns == 0) { echo “</tr>”; } } if ($count % … Read more
This query might help except ‘terms’ field bcoz there is no mapping from contract table to any other tables. select title,salary,descr,req,duties, county,name as comapny_name,job_location from job j join job_location jl on j.jid=jl.jid join location l on jl.lid=l.lid join job_company jc on jc.cid=j.jid join company c on c.cid=jc.cid 2 solved How to perform mysql joins in … Read more
To get the most recent row of data by sender and receiver, you can use a self join as follows: select * from messages msg where sent = (select max(sent) from messages msg_ where msg_.fromperson = msg.fromperson and msg_.toperson = msg.toperson) See how it works in this Fiddle 0 solved MYSQL Select group by order … Read more
if(!$k) { echo “Koneksi Gagal <br>”; echo mysqli_errno(); } else { echo “Koneksi Berhasil”; } Either of your if-else will run and write something to the response. you can’t redirect after writing the response. To redirect set header(“Location : select.php”); before echo or any other output solved Can’t redirect to another page in PHP
You can do self join. SELECT A.Artist FROM Album A INNER JOIN Album B ON A.Artist=B.Artist AND A.Year=B.Year WHERE A.Type=”LIVE” AND B.Type=”STUDIO” Hope this helps. 0 solved How do I write this query in SQL? [closed]
Keeping the code pretty generic here, but presumably you’re currently doing something like this: // output a table header while ($row = mysql_fetch_assoc($members)) { // output a table row } // output a table footer If you want to begin a new table periodically in that loop, you’d need to add a condition to determine … Read more