Based on the view you want to display, your models are incorrect and they need to be public class MemberPaymentVM { public string MemberName{ get; set; } public string TransactId { get; set; } [DisplayFormat(DataFormatString = “{0:d}”)] public DateTime PayDate { get; set; } public IEnumerable<CategoryAmountsVM> Payments { get; set; } [DisplayFormat(DataFormatString = “{0:C}”)] public … Read more
You can insert many values into SQL with a single command (though not recommend, use PDO), such as INSERT INTO MyTable ( Column1, Column2 ) VALUES ( Value1, Value2 ), ( Value1, Value2 ) If using jQuery, you can use $.post() to send data to your web server (PHP). Here’s an example: var items = … Read more
If you just want the max score per student you can aggregate the rows before joining: select s.id_student, u.name, u.role, s.status, u.no_phone, s.exam_status, sc.score from student s join user u on u.username = s.id_student join ( select Max(score) as score, id_student from score group id_student )sc on sc.id_student = s.id_student where mod(s.id_student, 2) = 0 … Read more
SELECT Category, Tag1Value FROM table_name t1 WHERE EXISTS (SELECT 1 FROM table_name WHERE Tag2Value = t1.Tag1Value) UPDATE Try this : SELECT res.Category, res.tag, COUNT(res.tag) FROM (SELECT DISTINCT Category, Tag1Value tag FROM table_name UNION ALL SELECT DISTINCT Category, Tag2Value tag FROM table_name) res GROUP BY res.Category, res.tag HAVING COUNT(res.tag)>1 It return : category | tag ———————————– … Read more
Found this to be an issue with SELinux that is not allowing httpd network connections. Executing: setsebool -P httpd_can_network_connect=1 Solved the problem. solved PHP not connecting to Remote MySQL [duplicate]
If the value is comma-separated (and not comma+space separated), you can use FIND_IN_SET: SELECT * FROM `table` WHERE FIND_IN_SET(‘lorem ipsum’, `column`); 2 solved mysql: how to select imploded array value [duplicate]
Try joining between client and test table like: SELECT c.forename, COUNT(c.forname) FROM Client c INNER JOIN Test t ON c.clientNo = t.clientNo WHERE c.forename=”Jim” AND t.status=”PASS” GROUP BY c.forname 2 solved How would I right a select statement to query this database?
From what I understand, you have two questions: How to put checkboxes on your CRUD list in order to delete all items at once. It seems that you are using update_list() to load all items on your table. Since thats the case, you need to add an extra <td> in that row to that iteration … Read more
$servername = “localhost”; $username = “username”; $password = “password”; $dbname = “myDB”; $conn = new mysqli($servername, $username, $password, $dbname); $sql = “SELECT * FROM APPUsers WHERE Phone LIKE ‘%$phone%'”; $result = $conn->query($sql); Above there is a fast solution , but it is not safe , because is vulnerable to injection … Below let’s see how … Read more
Just solved it myself by using: try: query = “””SELECT * FROM `v_someview` WHERE `id` = %s LIMIT %s;””” x.execute(query,(str(id),int(l))) except Exception as ex: #some code So I’m declaring that i’m going to use a string (%s) but casting that parameter to an int(). 2 solved Python – MySQLi parametized query with %d
Define the variable: $return = array(); Problem solved. But I really hope you’re not creating a new database connection every single time you want to select data, and never closing any of those connections… 3 solved Undefined variable error when no MySQL query produces no results [closed]
You will need to use JavaScript. My example uses jQuery. The other examples cited are a little more complicated, so I made this for you. // find the elements var $form = $(‘form’); var $buttons = $form.find(‘input[type=button]’); // event logic $buttons.click(function(e) { $buttons.attr(‘disabled’, false); $(this).attr(‘disabled’, true); }); Put this in the onload or DomReady handler … Read more
Code should be <?php #FileName = “Connection_php_mysql.htm” #Type = “MYSQL” #HTTP = “true” $hostname_Main_DB = “localhost”; $database_Main_DB = “mydb”; $username_Main_DB = “root”; $password_Main_DB = “”; $con = mysqli_connect($hostname_Main_DB,$username_Main_DB,$password_Main_DB, $database_Main_DB) or die ( “Failed to connect to MySQL: ” . mysqli_connect_errno()); $db=mysqli_select_db($database_Main_DB,$con) or die( “Failed to connect to MySQL: “.mysqli_connect_errno()); ?> You should remove “new”. For … Read more
You can change the error reporting to stop reporting on deprecation warnings. See here. However you should very seriously considering updating the code to use a non-deprecated extension such as MySQLi or PDO_MySQL. Edit: Also the image you supplied suggests that you have not supplied the parameters for connecting to the database. 1 solved How … Read more
You are inserting a table – each select is a row, each comma delimited item in the selects is a field. Each select has 2 fields, while the parenthetical field list has 3 fields. Try something like: INSERT INTO attendence (FName, LName, Mark) $FName, $LName, $Mark To use your select test setup: INSERT INTO attendence … Read more