Assuming you want a figure of 0 for any month and / or city which doesn’t have any sales, but where there are sales for other cities for that month then something like this:- Cross join a pair of subselects, one to get a list of the months used and one to get a list … Read more
Since you want to get 80 rows for both text and NO text, you can use UNION ALL. You can also order your data as per your requirement: (SELECT first_column, last_column FROM MyTable WHERE last_column = ‘text’ ORDER BY first_column LIMIT 80) UNION ALL (SELECT first_column, last_column FROM MyTable WHERE last_column = ‘NO text’ ORDER … Read more
Just switch name and count in your select select name,count(*) from db.db group by name order by name desc 1 solved count(*) column to the right of the data? [closed]
You need two counters Absolute Counter (always 1, 2, 3, 4, 5, etc). Rank Counter – it counts from 1 but if the scores are same, it does not update. As soon as scores are different, it updates with the absolute counter. Sample Code $counter = 1; // init absolute counter $rank = 1; // … Read more
In my situation it made more sense to instead ignore the table doesn’t exist errors. It is because my database system has little to no chance of ever changing and the updates in question never target the tables I am replicating. It is a legacy system that we’re slowly moving away from. slave-skip-errors=1146 The only … Read more
Hello, I have a query in mysql bench that works fine for every “reference” , but when using the same query in python returns different results [closed] solved Hello, I have a query in mysql bench that works fine for every “reference” , but when using the same query in python returns different results [closed]
If $monster is an array and mysql_real_escape_string as the name implies, takes a string, you must pass it a string. Since the function takes a $monster_name, perhaps you need to take that from the $monster array? Something like (without any idea of your code, just as an example, do not copy and paste 🙂 ): … Read more
Let’s say you have 2 tables: ID Name 1 Smith 2 Novak 3 Tarantino and the second table ID Cash 2 300 3 490 4 500 INNER JOIN will join records that have match in both tables, i.e. in the result table only ID 2 and 3 will be included, because they have match. Result … Read more
You can use the following query: SELECT cust_name FROM mytable GROUP BY cust_name HAVING COUNT(*) > 1 to get the cust_name values of duplicate records. Use this query as a derived table and join back to the original table to get the desired result: SELECT t1.* FROM mytable AS t1 JOIN ( SELECT cust_name FROM … Read more
You use JOIN but didn’t use on to connect two table, from your tables you might use actorID columns to be the connected condition. when you use an aggregate function you might use non-aggregate columns in group by SELECT a.lname,a.fname,AVG(c.salary) FROM Actor a JOIN Castings c on a.actorID = c.actorID group by a.lname,a.fname order by … Read more
Your password is not correct, try connect with: mysql -u root -p<YOUR_PASSWORD_HERE> Or, use mysqlsafe and change your root password. 1 solved mysql_exceptions.OperationalError | _mysql_exceptions.OperationalError: (1045, “Access denied for user ‘root’@’localhost’ (using password: YES)”) [closed]
I’m going to take a hot second to answer this. My query was correct. I simply didn’t have AutoIncrement turned on, because there was an invalid ID of 0, which I deleted. EDIT: FINAL CORRECT QUERY —————————————————————– INSERT INTO wp4t_postmeta (post_id, meta_key, meta_value) SELECT postmeta.post_id, ‘_attached_image’, posts.ID FROM wp4t_postmeta AS postmeta INNER JOIN wp4t_posts AS … Read more
You want to sort on the datetime (or if that doesn’t exist you could use the ID, but that is not how “it should be”) in descending order instead of ascending. Example query: SELECT `title`, `text` FROM `news` ORDER BY `datetime` DESC LIMIT 5 https://dev.mysql.com/doc/refman/5.7/en/sorting-rows.html solved How to order posts by date added [closed]
Maybe this is what you are looking for: SELECT * FROM products WHERE (product_type = “abc” AND (product_price >= 100 AND product_price <= 1000)) OR (product_type = “def” AND (product_price >= 2500 AND product_price <= 5000)) OR product_type NOT IN (“abc”, “def”) solved Is it possible to write this type of query with MySQL?
You can use a recursive CTE to get all the linked users: with recursive u as (select t.id, t.`Referral id`, t.Balance from yourtable t where id = 1 union select t.id, t.`Referral id`, t.Balance from u inner join yourtable t on u.id = t.`Referral id`) (select sum(Balance) from u) Fiddle 0 solved SQL SUM COLUMN … Read more