The error you are receiving as you’ve shown it is because this line is incorrect: SELECT * FROM `connections` WHERE 1″ First because it’s ending in an unnecessary double quotation mark. MySQL does not use double quotes but single quotes, and even still the other single quote is not there to match it. The single … Read more
There been a lot of great answers on this question of mine but if anyone looking for a quick fix in this case the following works for me <?php if ($fs1 > 0) { echo “<p style=”color:#0F3″>Win<p>”; } else { echo “<p style=”color:#F00″>Lose<p>”; } ?> with $fs1 being the row that i am getting the … Read more
If you’re using the deprecated mysql function: $user = “121”; $pass = “dummy1”; $email = “[email protected]”; mysql_query(“INSERT INTO users(username, password, email) VALUES(‘$user’, ‘$pass’, ‘$email’)”); On the other hand, using mysqli: mysqli_query($con, “INSERT INTO users (username, password, email) VALUES (‘$user’, ‘$pass’, ‘$email’)”); Note: where $con is the mysqli connection made variable. 3 solved Mysql insert into … Read more
There is a bug in the code. Change the while loop to this one: while ($row = mysql_fetch_array($results1)) { echo ‘<td><input type=”text” value=”‘ . $row[“first_name”] . ‘” ></td>’; } 0 solved How to show data from database into text in php
Sure. Create a time window and you can limit by that date $time = time() – (86400 * 30); // 86400 seconds in one day $sql=”SELECT * FROM table WHERE datefield > “” . date(‘Y-m-d H:i:s’, $time) . ‘”‘; That should yield you records within the last 30 days 2 solved Limit MySQL Results to … Read more
select user.name, user.country, data.best_time from user, data where user.user_name = data.user_name; solved Select from multiple tables using 1 column [closed]
A Student with just one Professor: A third table is not necessary, just add that foreign key (idp = Professor ID) in the Student Table so that you can do: SELECT * FROM Student JOIN Professor ON Student.idp = Professor.idp WHERE Professor.Name=”Jon” and this way you will get all the students who have Jon as … Read more
Replace insert_into with insert into And better use the YYYY-MM-DD date format insert into tb_loan (Product_Code, Customer_Code, Loan_Amount, Rate_Interest, Amount_Tenure, Emi_Amount, Emi_Start, Emi_End) VALUES (0,0,’10000′,10.37,’20’,’546.6′,’2013-10-25′,’2013-10-25′) 3 solved You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near [closed]
I can see you are using phpmyadmin, it is scripted too to return the values.This might be slow than the speed of your script which is definitely small. Did you consider to run the mysql queries from the command prompt?This might give you a clear difference. 4 solved Why does the PHP run faster than … Read more
Without LEFT JOIN See demo SQL Fiddle SELECT u.id, (SELECT w.wink_flag FROM winks w WHERE w.to_id = u.id GROUP BY w.to_id) AS WINK_FLAG, (SELECT f.fav_flag FROM favourite f WHERE f.to_id = u.id GROUP BY f.to_id) AS FAV_FLAG FROM users u WHERE u.id != 56 0 solved There are 3 tables users,winks and favourite [closed]
I think it will be helpful for you. get the result from MYSQL table between two dates in php. try this code: <?php $con=mysqli_connect(“localhost”,”root”,””,”database_name”); $first_date=$_POST[“first_date”]; $second_date=$_POST[“second_date”]; $sql=mysqli_query($con,”SELECT * FROM `table_name` WHERE `date` BETWEEN ‘”.$first_date.”‘ AND ‘”.$second_date.”‘ “); ?> solved I am trying to fetch data between date
Generally the best way to do this, is to upload the file to your server, and then store the path to it in the database. File Upload: http://php.net/manual/en/features.file-upload.php You need to choose a database, MySQL is a common and free option: https://www.mysql.com/ As mentioned in comment below, (I haven’t used it before but had a … Read more
The ORDER BY clause should be the last, but you have to specify fields to be aggregated. Such as: SELECT surname, count(*) FROM people WHERE user_token=’$user_token’ GROUP BY surname ORDER BY surname 1 solved SELECT * FROM people WHERE user_id=’$user_id’ ORDER BY time GROUP BY surname [closed]
https://www.codeschool.com/search?utf8=%E2%9C%93&loc=hero&query=sql Code school is a really good introduction to most concepts regarding SQL, but it is only really possible to have a really good understanding if you truly start with the basics so I would suggest starting here and then spending quite a few hours just messing around with an sql database of your own. … Read more
Currently you are using one big <form> element for all your entries. When sending that form, the actual values get overridden many times and you just see the last one. To solve this, you could, e.g., make a form out of every entry like this: echo “<html>”; $c = mysql_connect(“localhost”, “root”, “”); mysql_select_db(“test”, $c); $query … Read more