this is a suitable time to utilize the do while loop the way it works is it will execute the statement within the block without evaluating any conditions and then evaluate the condition to determine if the loop should run again this is what your program could look like #include <iostream> using namespace std; int … Read more
Check this <html> <head> <meta charset=”utf-8″> <meta name=”viewport” content=”width=device-width, initial-scale=1″> <link rel=”stylesheet” href=”https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css”> <script src=”https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js”></script> <script src=”https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js”></script> <script> $(document).ready(function () { var container = $(“#html2”); $(“#CreateDiv”).change(function () { $(‘#html2’).html(”); var strBlocksHTML = ”; var selectedvalue = $(“#CreateDiv option:selected”).val(); for (var i = 0; i <= selectedvalue; i++) { for (var n = 0; n < … Read more
From you saying the only difference is 1 becomes 2 I’m guessing you are just trying to run the loop again for a second user, perhaps a dictionary here, then you could just iterate the loop you already have constructed for each user in the dicitonary, you would have to touch up your loops I … Read more
Do you mean something like the following? echo ‘<td>’ . ($data[‘temperature’] < 5 ? ‘Cold’ : ‘Warm’) . ‘</td>’; The above uses the ternary operator as a contracted if/else within a table cell. 1 solved Condition inside table [closed]
As explained in previous answer: StringBuilder buf = new StringBuilder(); for (int i = 1; i <= 5; i++) { buf.append(i); for (int j = 1; j <= i; j++) { System.out.println(buf); } } solved Triangular number pyramid in java [closed]
You declare unsigned short hex_v_info (2 bytes on my system), then read data from with fscanf(fp ,”%x”, &hex_v_info) where the format string %x expect the address of an int (4 bytes on my system). This will certainly overwrite data unexpectedly. unsigned short **v_info but you store an array of int [s_votes]. If your pointers are … Read more
Try This $i = 0; $j = 1; echo $i; $flag = 1; $inc = 0; for($k = 0; $k <= 10; $k++) { $inc++; if($flag == 0){ echo $i; if($inc == 2){ $flag = 1; $inc = 0; } }elseif($flag == 1){ echo $j; //$flag = 0; if($inc == 2){ $flag = 0; $inc … Read more
I am sorry but scanf does not work that way. To write the value the user types in at the prompt, as n[i], scanf needs an address (in memory). C is in this regard intentionally rudimentary, more so than a language like Python or JavaScript. The way you wrote your code, you end up passing … Read more
By the time p3 equals 10, it will never re-enter the while (p3 < 10) loop (because once you’ve incremented it to 10, it will never be less than 10 and will never re-enter that loop). So yes, p and p2 do increment, but they never get printed because p3 == 10 at that point … Read more
for(int i = 0; i < myShapes.length; i++) { System.out.print(“Object ” + i + ” is a”); if(myShapes[i] instanceof Rectangle) System.out.print(” rectangle: “); else if(myShapes[i] instanceof Circle) System.out.print(” circle: “); else if(myShapes[i] instanceof Box) System.out.print(” box: “); else if(myShapes[i] instanceof Cylinder) System.out.print(” cylinder: “); System.out.println(myShapes[i].toString()); } 3 solved How to identify objects in array using … Read more
I don’t think your for loop is doing what you want it to do. Like, at all. temps[i] = in.nextInt(); // This is sensible enough closest = Math.abs(temps[0]); // Every time your loop runs, the closest value to 0 is… the absolute value of the first int in the array? //System.err.println(temps[i]); if (closest > 0) … Read more
concentrate on this piece of code for (i = 0; i <= 5 ;i++) { –> for (space = 5 – i; space <= 4; space++) { printf(” “); } in first iteration of inner for loop space value is space: 5-0 = 5 as the i:0 and for we have condition space <= 4 … Read more
IMO, best will be to use a Dictionary<string,int[][]>. During creation you will place a new array (which you just created) and assosiate it to the key “a” + i. To get this array, just get the value attached to the relevant key. Something like (C#-like pseudo code): var map = new Dictionary<string,int[][]>(); for(int i=1;i<10;i++) { … Read more
According your question and your comment, I assume you have no problem with the text and input. So the point is how to split up mark and grade? You can use zip() to do this # This is an example for Josh, assuming you already have list call lines, # lines = [(mark1, grad1), (mark2, … Read more
You never update the value of GuessedNumber inside the loop. Therefore, if the code enters the loop, it will never leave it because RandomNumber != GuessedNumber will always be true. You need to do something like this: import random RandomNumber=(random.randint(0,100)) GuessedNumber=int(input(“Guess any whole number between 0 and 100! “)) while RandomNumber != GuessedNumber: print(“Unlucky guess … Read more