[Solved] How can I create a SIP connecton using Liblinphone interface class?
[ad_1] Absolutely an interface cannot be initialized. Because it has no method implementation. It’s not a class! I should use classes that implement these methods. In fact I should use org.linphone.core (Library) instead of LinphoneCore (Intreface) [ad_2] solved How can I create a SIP connecton using Liblinphone interface class?