[Solved] How can I create a SIP connecton using Liblinphone interface class?

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Absolutely an interface cannot be initialized. Because it has no method implementation. It’s not a class!

I should use classes that implement these methods.

In fact I should use org.linphone.core (Library) instead of LinphoneCore (Intreface)

solved How can I create a SIP connecton using Liblinphone interface class?