You’re not calling your lambda as I’ve explained in my comment, but if you want it inline you can test as: if (lambda x: True == True)(None): print(“yes”) # prints if (lambda x: False == True)(None): print(“yes”) # doesn’t print Or more general, since you’re not actually using any arguments in your lambdas: if (lambda: … Read more
You are facing problem on this line (result => result.SiteUrl.Contains(last.ToString()); Can you please check that SiteUrl is type of string otherwise it not going to work for you. because last is type of string and Contains is method supported by string type … or otherwise last need to be enumebrable collection and siteurl also enumerable … Read more
.append() is an in place update, and returns None, so your current generator is creating a list of None which can’t be compared by sorted(). That aside, you don’t need to keep track of your newly split items with map() as it’s a generator that is being fed into sorted(). Try: >>> my_list = [“a,a”, … Read more
yshavit: What you’re trying to do isn’t easy/natural to do in Java. You’re basically trying to write an expression which creates and immediately invokes a method, basically as a way of grouping a bunch of statements together (and also providing an enclosed scope) to get a single value. It’s not an unreasonable thing, and in … Read more
If you want to create a function which adds 1 to its input, the method to create that function doesn’t need an parameters… but then you need to call that function in order to execute it. I suspect you wanted: import java.util.function.Function; public class LambdaExpression { public static Function<Integer, Integer> create() { Function<Integer, Integer> f … Read more
Not 100% sure what you are asking, but I’ll give it a try. Assuming you have a list of Points… List<Point2D> points = Arrays.asList(new Point2D.Double(12., 34.), new Point2D.Double(56., 78.)); … you can turn that list into a 2D-array like this: double[][] array = points.stream() .map(p -> new double[] {p.getX(), p.getY()}) .toArray(double[][]::new); … or into a … Read more
var temp = dbconnect.tblAnswerLists .Where(i => i.StudentNum == studentNumber && i.username==objstu.Return_SupervisorUserName_By_StudentNumber(studentNumber)) .ToList() // <– This will bring the data into memory. .Select(i => new PresentClass.supervisorAnswerQuesttionPres { answerList = Return_Answer_List(studentNumber,i.dateOfAnswer.Value.Date), questionList = Return_Question_List(studentNumber, i.dateOfAnswer.Value.Date), date = ConvertToPersianToShow(i.dateOfAnswer.Value.Date) }) .GroupBy(i => i.date) .OrderByDescending(i => i.Key) .ToList(); temp will actually be of type List<IGrouping<string, PresentClass.supervisorAnswerQuesttionPres>>. 2 solved Group … Read more
It’s not possible. The best solution will be using a function with *args and possible **kwargs: argsneeded = [‘foo’, ‘bar’] def whatever(**kwargs): if not all(x in kwargs for x in argsneeded): raise ValueError(‘required kwarg is missing’) 0 solved Python: How to get names of arguments in a list in a lambda?
This is actually quite simple, despite the convoluted solutions others have offered: Map<String, List<String>> map = placements.stream() .collect(groupingBy(Placement::getFutureLinkId, mapping(Placement::getId, toList()))); 1 solved Convert a Collection to Map using java 8 streams [closed]
I think the problem is the new ObjStr2() in your second collector. You’re using the same starting element for all groups. You’re concatenating everything to the same object, and because this is mutable, everything is appended to that same object. Instead, make your doReduce return a new object: static ObjStr2 doReduce(ObjStr2 a, ObjStr2 b) { … Read more