You can use this : Since the data in items is array of dictionaries and link is not in internal array it is main dictionary so you can easily get this by passing link in as key. let link = “http://www.flickr.com/services/feeds/photos_public.gne?tags=swimming&format=json&nojsoncallback=1” let urlString = link let url = URL(string: urlString) URLSession.shared.dataTask(with:url!) { (data, response, error) … Read more
It’s pretty much the compressed format of JSONArray, I’ve seen it few times, some systems use it to lower the amount of data that gets transferred. You can try something like this (edit how you need it, as this is only a basic concept): // Let us assume your JSON is loaded in jsonString variable … Read more
If your on php 4.5 or above you can use the JSON_PRETTY_PRINT. $json_string = json_encode($data, JSON_PRETTY_PRINT); solved Display JSON File content using PHP [closed]
UPDATE I solved this way. Object.keys(data).length Thanks for yours downvote! solved json check empty data
you can refer how to set the attribute of the column at the image. solved It does not add in my database, the code seems right though [closed]
How can i create the correct JSON data in an Android app required for a Java Jax RS REST POST Api accepting a List of JSON Objects solved How can i create the correct JSON data in an Android app required for a Java Jax RS REST POST Api accepting a List of JSON Objects
Try this var desriptionArray = [String]() for dataValues in responseObject[“result”] as! [[String: AnyObject]] { let name = dataValues [“description”] as! String desriptionArray .append(name) } OR for (index , element) in (responseObject[“result”] as! [Any]).enumerated() { let nameDict = element as! [String : AnyObject] let strDecription = nameDict[“description”] as! String desriptionArray .insert(strDecription, at: index) } solved While … Read more
Try this, it should must work. <?php $data = file_get_contents(“https://httpbin.org/ip”); print_r($data ); 1 solved How to read json data from a website in php?
Convert the Json string to Hashmap like below using Google’s Gson, then you can interate through the hashmap String jsonString = “Your JSON string”; HashMap<String, JsonObject> map = new Gson().fromJson(jsonString, new TypeToken<HashMap<String, JsonObject>>(){}.getType()); 2 solved Any suggestions to deserialize this json with Gson? [closed]
Your code cannot work. According to the given JSON the root object is an array [[String: Any]] and there is no key result at all. let json = “”” [{“id”:1,”class”:”A”,”Place”:{“city”:”sando”,”state”:”CA”}},{“id”:1,”class”:”B”,”Place”:{“city”:”jambs”,”state”:”KA”}}] “”” let data = Data(json.utf8) do { if let json = try JSONSerialization.jsonObject(with: data) as? [[String: Any]] { for item in json { if let … Read more
Thank you DroiDev and MohamedMohaideenAH. Finally i got the solution private void parseJson(JSONObject jsonObject){ try { for(int i = 0; i < jsonObject.length(); i++){ if(jsonObject.get(jsonObject.names().getString(i)) instanceof JSONObject){ Log.e(“===Start===”, “===Start===”); Log.e(“objectName”, jsonObject.names().getString(i)); JSONObject singleObj = new JSONObject(jsonObject.get(jsonObject.names().getString(i)).toString()); Iterator<String> keys= singleObj.keys(); while (keys.hasNext()){ String keyValue = keys.next(); String valueString = singleObj.getString(keyValue); if(!isJSONObjectOrString(valueString)) Log.e(keyValue, valueString); } Log.e(“===End===”, “===End===”); … Read more
For above json you must have this classes below: Example.java package com.example; import javax.annotation.Generated; import com.google.gson.annotations.Expose; public class Example { @Expose private To to; public To getTo() { return to; } public void setTo(To to) { this.to = to; } } To.java package com.example; import java.util.ArrayList; import java.util.List; import javax.annotation.Generated; import com.google.gson.annotations.Expose; public class To … Read more
Here is one way to do it. You need to get the table object using jquery selector. Then you need to loop the results property of the json data using for keyword. For each object of the result, get the property of subject, date and time_start using property accessor. Create a row string such as … Read more
Assuming you have a file in bundle (as it wasnt clear from the question), you can read the file with following code: NSString * path = [[NSBundle mainBundle] pathForResource:@”YOU_FILE_NAME” ofType:@”txt”]; NSString *jsonString = [NSString stringWithContentsOfFile:path encoding:NSUTF8StringEncoding error:nil]; then print it to console using: NSLog(@”%@”,jsonString); 4 solved I have a JSON file attached below and i … Read more
edit: Here use this now you can one way serialize a class structure with this nifty little bit of code that I added to address my problem with f**** discord.py ! end edit There is no fire and forget option that would disentangle a mass of information. The way of creating this solution would be … Read more