[Solved] How can I analyse an response.text in Python?

As you have a dictionary of dictionaries, accessing each dictionary value will give you another dictionary. You can then access the values from that dictionary in the same way. For your particular example, you can do the following: >>> master_dict[“Item”][“last_data”][“S”][“question”] ‘question question question?’ If instead, you want to access all occurrences of a certain key … Read more

[Solved] Converting a massive JSON file to CSV

A 48mb json file is pretty small. You should be able to load the data into memory using something like this import json with open(‘data.json’) as data_file: data = json.load(data_file) Dependending on how you wrote to the json file, data may be a list, which contains many dictionaries. Try running: type(data) If the type is … Read more

[Solved] Store value from JSON to a variable [closed]

Based on this file https://pastebin.com/Z3vJsD77 you posted above. You can directly access the chargeLimitSOC property from this model like following – let chargeLimitSOC = chargeState.chargeLimitSOC Relevant part in your model is here – open class ChargeState: Codable { open var chargeLimitSOC: Int? enum CodingKeys: String, CodingKey { case chargeLimitSOC = “charge_limit_soc” } } 1 solved … Read more

[Solved] how to add new array in JSON using PHP with this format? [closed]

Data field is array of objects? If yes, try something like this… $array = [ “table-name”=>”Beta”, “created-on”=>”May 03, 2021”, “token”=>”6kh3o0oRLZreJ9K”, “columns”=>”Name,Org,Address,Mobile,Email,Pass”, “data” => [] ] $data = [ “Name” => $_POST[“fullname”], “Org” => $_POST[“organization”], “Address” => $_POST[“address”], “Mobile” => $_POST[“phone”], “Email” => $_POST[“email”], “Pass” => $_POST[“password”] ]; array_push($array[“data”], $data); $json = json_encode($array); 2 solved how … Read more

[Solved] How to take element from two json arrays in jquery

Try this, function compareArr(arr1, arr2) { var longArray = arr1.length >= arr2.length ? arr1 : arr2; var shortArray = arr1.length < arr2.length ? arr1 : arr2; return resultArr = longArray.filter(function (v) { return shortArray.filter(function (iv) { return v.Lattitude === iv.Lattitude && v.Location === iv.Location && v.Longitude === iv.Longitude; }).length === 0; }); } var resultArr … Read more

[Solved] JSON Structural Difference

First and foremost, the example JSONs are not valid JSONs because keys in JSON has to be enclosed in “. However, if you do have two valid JSON strings, you could parse them into a dictionary, then compare the structure of the dictionary using this function: def equal_dict_structure(dict1, dict2): # If one of them, or … Read more

[Solved] JSON to UITableView error

objectAtIndex is a method for NSArray. Your Menu object is an NSDictionary. You need to get the array within the Menu dictionary like this: NSArray *myArray = [Menu objectForKey:@”GetMenuMethodResult”]; and use myArray as the source for your rows. 0 solved JSON to UITableView error

[Solved] An example on how to convert this data format to JSON? [closed]

Well, you haven’t given us any clues at all what the data format is. So based on what I see in your question, just 6 rows of data, I would suggest: {rows:{row1:’@Scsi_test’,row2:'(iotest)’,row3:’scsi’,row4:’dkdkdkdkdkdkddk’,row5:’dkdkdkdkdkdkddk’,row6:’dkdkdkdkdkdkddk’}} 1 solved An example on how to convert this data format to JSON? [closed]

[Solved] defaultdict key default value issues

I am guessing, that the defaultdict is not what you want to use. Default values should be declared in the second argument of the get method. problem = [{‘lastInspection’: {‘date’: ‘2018-01-03’}, ‘contacts’: []}] default_inspection = { ‘date’: ‘2018-01-03’ } for p in problem: # default_inspection is returned, when ‘lastInspection’ is not present in the json … Read more

[Solved] How would I be able to create brackets around my json file using PHP?

Try it like this: $employee_data = array(); $categories = array(); $employee_data[“mapwidth”] =”2000″; $employee_data[“mapheight”] =”2000″; while($row = $result->fetch_array(MYSQL_ASSOC)) { $categories[] = $row; } $employee_data[“categories”] =$categories; echo json_encode($employee_data); Refer to this answer to further improve your code. 4 solved How would I be able to create brackets around my json file using PHP?

[Solved] JSON.stringify and angular.toJson not working as expected

In Javascript, two strings are equal === if they have the same data. Ex: ‘{“light”:true,”new”:true,”available”:false}’ === ‘{“light”:true,”new”:true,”available”:false}’ Note: In other languages like Java, two strings are equal == is they refer to the same instance. In that case, two strings with same data would not be ==. 1 solved JSON.stringify and angular.toJson not working as … Read more

[Solved] Passing JSON to new activity – Android app [duplicate]

Thank you all for the answers. This has helped me understand how to use intents and I was able to solve my problem with this: Activity 1 String json= textViewResult.getText().toString(); Intent i = new Intent(Activity1.this, Activity2.class); i.putExtra(“Data”,json); startActivity(i); Activity 2 Bundle b = getIntent().getExtras(); String json = b.getString(“Data”); TextView jData = (TextView) findViewById(R.id.textView1); jData.setText(json); solved … Read more