I assume that you expect, that tooltip should be displayed in on each point. All series except scatter have to be sorted and only one point for a one x-value. So you can use scatter series with defined lineWidth. series: [{ type:’scatter’, lineWidth:2, data: Data }] http://jsfiddle.net/LtkX2/1/ 3 solved Highcharts has incorrect chart [closed]
You need to add the validation to the form element and set the required rule to the checkbox <form id=”myform”> <input type=”checkbox” value=”agree” name=”agree” id=”agree” /> <input type=”submit”> </form> then jQuery(function ($) { $(“#myform”).validate({ rules: { agree: { required: true } }, messages: { agree: “Please agree the terms and conditions” } }); }); Demo: … Read more
There is no need to iterate, jQuery will do this for you very conveniently. It’s not very clear from the question what exactly you want to do, but you can: Switch .plus to .minus with $(“.plus”).toggleClass(“plus minus”) Toggle .plus and .minus on all elements that have either with $(“.plus, .minus”).toggleClass(“plus minus”) 1 solved How to … Read more
Your attempt does not work because the click event handler is attached to the whole span element, which comprises the icon and the link. To make it work, you have to make 2 small modifications to the javascript code: attach the click handler to the i element (which holds the icon) using this selector: .tree … Read more
Your second form has the following class no-spacing which will override the margin-left in your shakeForm function due to the !important .no-spacing { padding: 0px !important; margin: 0px !important; } solved JavaScript not working properly on page
Try this once!! function loadpage(){ //only for one textarea var text = document.getElementByTagName(“textarea”).value; $.ajax({ type: ‘POST’, url: ‘lib/ajax.php’, data: {‘data1’: text}, success: function(res){ $(“#inneroutput”).html(res); } }); solved how to send data from js to php? [closed]
As you know, the correct fix here is to fix those links server-side, ideally by removing the scheme entirely, to create scheme-relative URLs like this: <script src=”https://cdnjs.cloudflare.com/ajax/libs/jquery/3.1.1/jquery.min.js”></script> But you’ve said you can’t do that. So: You can readily find all a elements via document.querySelectorAll. You can easily loop through the result. …and get their href … Read more
You have to move one ‘});’ of the bottom before the else: //run the function for all boxes $(“.box”).each(function () { var thisBox = $(this); var url = thisBox.href; var infoBox = $(“.info”, thisBox); thisBox.data(‘height’, $(this).height()); thisBox.click(function () { if (!thisBox.hasClass(“opened”)) { thisBox.addClass(“opened”); $(“img”, box).fadeOut(“slow”, function () { infoBox.css({ “visibility”: “visible”, “height”: “auto” }); infoBox.load(url, … Read more
Change the height by inherit in .ibm-card__image class .ibm-card__image { height: inherit; width: 38%; } 10 solved Image height not getting set to 100% of card
Your modified menu >> Menu Resizable Static- Better Version >> Not Resizable 2 solved Horizontal menu CSS – replicate the menu of donebynone.com
So, what you want is to reorder the elements when the window is resized, right? You can try the following code… $(function() { var screenBig = $(window).width() >= 640; $(window).resize(function() { if($(window).width() < 640 && screenBig) { resizeSmall(); screenBig = false; } else if($(window).width() >= 640 && !screenBig) { resizeBig(); screenBig = true; } }); … Read more
.closest goes up in the DOM tree to try and find the element you make it look for. There is no .travelClass element further up the tree, from the position of your .travelMode element. You need to go up to the TD or the TR first, and then select your way sideways/down to the element … Read more
The example is with src code so he import come from ./src. But you install dependencies so library is in instagram-private-api folder import { IgApiClient } from ‘instagram-private-api’; solved NodeJS Instagram private API client in react JS [closed]
The jsondata value is JSON text. It starts with [, which means it’s a JSON array. To process it, you should use a JSON parser. See How to parse JSON in Java. Once you have parsed it, you should have a String[] or a List<String>, with 2 values. Both values start with data:image/jpeg;base64, followed by … Read more
You can access them like this, using the rest operator for arguments var mainobject = { val1: ‘text1’, val2: ‘text2’, val3: ‘text3’, val4: ‘text4’, val5: ‘text5’ }; function a(…args) { var obj={}; args.forEach((e) => { obj[e]=mainobject[e]; }) return obj; } console.log(a(‘val1’, ‘val4’)); 3 solved How to return values from a object matched by a array?