You can use jQuery along with React and ES6. At the end of the day, it’s all JavaScript. However, if you structure your code correctly with React components, you should not need to use jQuery selectors to make any changes to the DOM. 1 solved JavaScript ES6 project and jQuery
style only gives you access to the inline style of an element. To access all the styling properties, use getComputedStyles. More details and examples here. 1 solved Apply parts of the CSS attributs of a class to a DOM element [closed]
the second alert(projectId); outside the “click” event handler runs as soon as the page loads. Inevitably this is before your “click” handler can possibly be executed, because the user has likely not had time to click on it, and even if they had time, there’s no guarantee that they will. Therefore the variable projectId is … Read more
What about ? <body class=”en”> <script> if($(‘body’).hasClass(‘de’)) { $(‘body’).html(‘<div id=”de”>some html</div>’); } else if($(‘body’).hasClass(‘en’)) { $(‘body’).html(‘<div id=”en”>some other html</div>’); } else if($(‘body’).hasClass(‘es’)) { $(‘body’).html(‘<div id=”es”>another html</div>’); } else { … } </script> Dynamic : var bodyClass = $(‘body’).attr(“class”); var bodyValue = $(‘#’ + bodyClass).html(); $(‘body’).html(bodyValue); But you should verify that body has a class and … Read more
Without the quotes, nameOrg is an invalid JavaScript variable. $(nameOrg) Here’s the right way to select an element by it’s ID: $(‘#nameOrg’) Reference: https://api.jquery.com/id-selector/ Also, I see your html document does not contain any reference of jQuery. Make sure you are importing the library. <script src=”https://ajax.googleapis.com/ajax/libs/jquery/2.2.4/jquery.min.js”></script> I strongly suggest wrapping the code in a jQuery … Read more
You need to set the style of the body element if the string you are checking for is present in the URL. if(window.location.href.indexOf(“player=1″)!=-1) document.body.style.backgroundColor=”#000”; Alternatively, to avoid setting inline styles, you can create a new class and apply it to the body if the string you are checking for is present. body.player1{ background:#000; } if(window.location.href.indexOf(“player=1”)!=-1) … Read more
What I did is to change id=”getImg” to class=”getImg” because id attribute should always be unique. Instead of getting the click event of the image, I used the click event of <a>, then located the <img> using find(). I also added an id to the big image, because there are two instance of .img-big, which … Read more
Check this out, i add comment for easy understand this code var str=”@hello, world how are you. I @am good”; str = str.split(‘ ‘); // split text to word array str = str.filter(function(word){ return word.includes(‘@’); // check words that using @ }).map(function (word) { return word.replace(/[^a-zA-Z^@ ]/g, “”) // remove special character except @ }); … Read more
$.each() doesn’t return what the callback function does, you need to use $.map, then .join() to combine all the results back into a string. But a simpler way is to take the loop out of the concatenation, and instead append to the string in the loop. var htmlString = ‘<section class=”content-header”><h1>Employee</h1></section><!– Main content –><section class=”content”><div … Read more
You must include the JS file where the Slider function is defined. Maybe jQuery Slider, from jQueryUI? <link rel=”stylesheet” href=”https://code.jquery.com/ui/1.11.4/themes/smoothness/jquery-ui.css”> <script src=”https://code.jquery.com/jquery-1.10.2.js”></script> <script src=”https://code.jquery.com/ui/1.11.4/jquery-ui.js”></script> <link rel=”stylesheet” href=”http://stackoverflow.com/resources/demos/style.css”> Here is the working demo. 12 solved Uncaught TypeError: Not a function
Try using a function that returns an array instead, and do a loop inside there. $(‘#calendar’).fullCalendar({ editable: true, events: function(){ var arr = []; for(var i = 0; i <= 10; i++){ arr.push({ title: ‘All Day Event’, start: new Date(y,m,i) }); } return arr; }() // <– Here we execute the function, so it evaluates … Read more
Yo cant individually style elements in options. This element is rendered by the OS, not HTML. It cannot be styled via CSS. There are replacement plug-ins that look like a SELECT, but are actually composed from regular HTML elements that CAN be styled. Use instead https://github.com/HubSpot/select or https://select2.org/ solved How to change font size inside … Read more
What you’re looking for is possible with vanilla Javascript, jQuery, or a host of other libraries. jQuery is where I’d recommend you start. You can create new elements by passing html elements as strings to the jQuery function. See the “Creating New Elements” section of this page. Using append and remove as Muzammil mentioned, you … Read more
You do get your scrolltop in the console like that, on codepen, but likely not on local. Learn about $(document).ready(function(){ Always load the jQuery src first, after the body element, then the rest of the JS code. Or inline it after the body closing tag. But always the jQuery first. Then , depending on the … Read more
If you mean function foo(x){ return function(y){ return x+y; } } Then foo(5) returns a function that takes another parameter, (y). So foo(5)(6) inputs 5 to foo, and 6 to bar. foo(5)(6) returns 11 foo(4) returns a function(y){ return 4 + y;} foo(7) returns a function(y){ return 7 + y;} 3 solved Javascript function with … Read more