With a few tweaks to the JS and HTML, the following code works… $(‘body’).on(‘keyup’, ‘.qty_field’, function () { var sum = 0; $(‘.qty_field’).each(function() { sum += Number($(this).val()); }); $(‘.running_total’).html(sum); }); solved jQuery – update variable when input values changed
And I had finally figured out how to make it work colors: [ <?php $num_counts = count($count); $on = 1; foreach($count as $bit => $bit_counts) { if($bit == ‘STEEL’){echo”‘#FF9999′”;} else if($bit == ‘STEEL CROWN’){echo”‘#FF9999′”;} else if($bit == ‘SLIM’){echo”‘#9999FF'”;} else if($bit == ‘KYMERA’){echo”‘#FF2626′”;} else if($bit == ‘HYBRID’){echo”‘#FF2626′”;} else if($bit == ‘EZC’){echo”‘#FFFF26′”;} else if($bit == ‘EZR’){echo”‘#FFFF26′”;} else … Read more
Thank for the help guys, but I figured out what was wrong. On the spritesheet I was using, the medal wasn’t being selected properly, so nothing showed up. It was still being drawn. solved I can’t get a sprite to draw to the screen
If the search on http://musicbrainz.org/ws/2/artist/? returns more than one artist, the object returns an array in results.query.results.metadata[“artist-list”].artist So, to access the data, it would be quizCountry = results.query.results.metadata[“artist-list”].artist[0].area.name; quizYear = results.query.results.metadata[“artist-list”].artist[0][“life-span”].begin.match(/\d{4}/); quizBand = results.query.results.metadata[“artist-list”].artist[0].name; So, you’ll need to check if results.query.results.metadata[“artist-list”].count > 1 and change your code appropriately e.g. if(results.query.results.metadata[“artist-list”].count > 1) { quizCountry = … Read more
Yes, you can use server-side Java code as a mediator. Use JavaScript to POST data to an HttpServlet, via JavaScript’s XMLHttpRequest object. Then handle the data in your servlet. Once you’ve done your DB business, you can send a “All done!” response back, to be handled by your JS. I suggest reading up on the … Read more
var startPoint = {x:5,y:-26}; var endPoint = {x:13,y:-34}; var map=[]; for (i=startPoint.x;i<=endPoint.x;i++) { for(j=startPoint.y;j>=endPoint.y;j–) { map[i,j] = {x:i,y:j}; } } 4 solved How can i find some position near a position?
response is an object. result is an object. full is an object. Array1 and Array2 are, obviously enough, arrays. For mytext1: response.result.full.Array1[0] For mytext2: response.result.full.Array1[1] For mytext3: response.result.full.Array2[0] For mytext4: response.result.full.Array2[1] If you want to log everything in the array, use a simple for…loop: var arr = response.result.full.Array1; for (var i = 0, l = … Read more
No, that is not possible without authorization. You either have to authenticate yourself or let the user perform the authentication at client side and use Google’s user API with the token. Imagine Google giving your personal details to anyone just because he/she knows your email id, why’d they ever do that? 7 solved How to … Read more
Try this var items= { “people”: [ { “name”: “Person A”, “score”: 100 }, { “name”: “Person B”, “score”: 101 }, { “name”: “Person C”, “score”: 100000 }, { “name”: “Person D”, “score”: 555 } ] }; items.people.sort(function(a, b){ return a.score – b.score; }); console.log(items); it works as expected! 0 solved I want to sort … Read more
I am not entirely sure on what exactly you are asking but I understood it like that: You want to use the code from the JSFiddle in your own project and it does not work. If that is the case, I think you forgot to add a reference to JQuery in your code. Add this … Read more
Sounds like maybe jQuery UI’s Dialogs are what you’re looking for? All you do is set aside some HTML in a container (such as a Div) and then render the dialog box. Link: https://jqueryui.com/dialog/ To “create” the dialog, you’ll just need to create a dialog from the container whenever you need it to be visible. … Read more
For better understanding you can call ajax method as below $.ajax({ url: ‘https://prod.api.pvp.net/api/lol/euw/v1.1/summoner/by-name/kerrie?api_key=[key]’, type: ‘GET’, dataType: ‘JSON’, async: false, error: function(){}, success: function(resp){ // resp variable will be your JSON responce } } }); 1 solved jQuery AJAX not receiving JSON from http request
Right there on front page shows it passed in as the second argument start: function (event, $elem) { ^^^^^ 1 solved Reference DOM with $(this) after plugin [closed]
You can use .call(context[, params])and .apply(context[, arguments]) to do this. For example: function move(x, y) { this.style.left = x + “px”; this.style.top = y + “px”; }; // now this in move refers to the div element move.call($(‘div’)[0], 100, 200); But you can’t just overwrite this. solved How to modify “this” in javascript
Your regex doesn’t say what you think it says. ^([a-z0-9_\.-])+@[yahoo]{5}\.([com]{3}\.)?[com]{3}$ Says any characters a-z, 0-9, ., – one or more times. That later part where you are trying match yahoo.com is incorrect. It says y, a, h, or o, any of those characters are allowed 5 times. Same with the com so aaaaa.ooo would be … Read more