You should edit your CSS to hide your “Back to Top” button by default, and then show it when the show class is added. #toTop { display: none; background-color: #FF9800; width: 50px; height: 50px; text-align: center; border-radius: 4px; margin: 30px; position: fixed; bottom: 30px; right: 30px; transition: background-color .3s; z-index: 1000; } #toTop.show { display: … Read more
You can use map and replace \[\d+\]$ \[ – Matches [ \d+ – Matches one or more digits \] – Matches ] $ – End of string var errors = [ { name: “Emails[2]”, message: “Email is invalid” }, { name: “Role”, message: “Role is required” }, { name: “Role random [123]”, message: “Role is … Read more
return an array instead: function test(){ var price=”10″; var name=”apple”; var available=”yes”; var p = [price, name, available]; return (p); } var test = test(); console.log(test[0]); // price or an object: function test(){ var price=”10″; var name=”apple”; var available=”yes”; var p = { price: price, name: name, available: available }; return (p); } var test … Read more
Use numeric naming. Instead of one_two_txt, just use 1_2. This way, you can loop through it. $filled = 1; for($c = 0; $c <= 6; $c++) { if($filled == 0) { break; } for($r = 0; $r <= 20; $r++) { if(strlen($_POST[“” . $c . “_” . $r . “”]) <= 0) { $filled = … Read more
put all in document ready handler and see if helps: <script src=”https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js”></script> <script type=”text/javascript”> jQuery(function($){ var prev = ”; $(‘#zzz img’).click(function(){ if (prev != ”) $(‘#img_’ + prev).css(‘border’, ‘1px solid #eee’); prev = $(this).attr(‘id’).replace(‘img_’, ”); $(this).css(‘border’, ‘1px solid #535666’); $(‘#imgid’).val(prev); }); }); </script> Hoping that you are having jQuery plugin loaded before this script. solved … Read more
you can use xmlhttprequest, and the javascript : var xhr = new XMLHttpRequest(); // Create new XHR var url=”http://sample.com/change.php”; // The url var data=”data=sample&back=come”; xhr.open(‘POST’, url, true); // POST is method you can with `POST|GET` xhr.send(data); or it can be simplifer with jquery var url=”http://sample.com/change.php”; // The url var data=”data=sample&back=come”; $.post(url,data,function(callback){ alert(callback); }); and sure … Read more
The problem here is the order that this page is parsed. The PHP will first render the page on the server and then send to the browser. The javascript is then executed on the client-side. Think of it like this. Anything in-between the echo $_SESSION[‘fname_” + countItem + “‘] ; I’m surprised this isn’t throwing … Read more
.innerHTML isn’t a method. For jQuery, it’s $(this).html() or with the native API, it would be this.innerHTML. And use more sensible flow control constructs like a switch statement. Generally, .innerHTML comparison can be touchy. Use .text() instead when you’re only comparing the text content. $(“li.menu-item a.ui-link”).each(function() { switch ($(this).text()) { case “Accounts”: $(this).addClass(“AccountIcon”); break; case … Read more
You would use Javascript if you want the tooltip to change over the course of the form. For example, if you want to display a different tip after a button was clicked, then you would set the tooltip in the click handler for the button. If the tooltip will never change, then just include it … Read more
Just use an AJAX call: <div id=’some-container’>Loading…</div> <script type=”text/javascript”> $(document).ready(function() { $.get(‘@Url.Action(“Add”, “BankController”)’, function(viewResult) { $(“#some-container”).html(viewResult); alert(viewResult); }); }); </script> 5 solved Call Controller action from JavaScript [closed]
Use AJAX to load the remote sites into a hidden DIV as soon as your main page loads. When the user clicks on the link, hide the main DIV and show the corresponding DIV. Since AJAX runs asynchronously in the background, the loading will happen while the user is reading the main page, and hopefully … Read more
If you want the solution in JQuery, here you go: $(“.formGroup”).hide(); $(‘#chooseForm input:checkbox’).on(‘change’, function() { if($(this).is(‘:checked’)) { $(“#” + $(this).val()).show(); } else { $(“#” + $(this).val()).hide(); } }); A complete example: http://jsfiddle.net/exttq/ Hope it helps! 2 solved Need to display forms as per the checkboxes selected [closed]
This is the explanation of your code. Actually, ternary operator is the short form of if else condition. const dirY = 5; const dirX = -5; let y; let x; if(dirY != 0){ if(dirY < 0) { y = “N” } else { y = “S” } } else { y = “” } if(dirX … Read more
I was able to get this to work. I added a variable to determine that the selection is “true.” I also added a button to move to the next question so that the submit button / function is separate. 0 solved Values from Array Only Change Upon First Run of a Function
For uploading i suggest DropZoneJs After you upload videos , store them somewhere, like amazon s3 then , store link on database then , use temporary link to show them for your user, base on your business model Laravel Docs temporary link 3 solved How can do video playlist in laravel [closed]