jsonObj is an array thus you first have to iterate this array jsonObj.forEach(o => {…}); o is now an object. You have to iterate the keys/values of it for(let k in o) k is a key in the object. You can now alter the value o[k] = ‘WhateverYouNeed’ var jsonObj = [{ “key1”: “value1”, “key2”: … Read more
document.getElementById(“main”)? You don’t need to assign the first div an id, either. var div0 = document.createElement(“div”); var div1 = document.createElement(“div”); var div2 = document.createElement(“div”); div0.appendChild(div1); div0.appendChild(div2); document.body.appendChild(div0); 3 solved How do I create this with javascript [closed]
Your if statement isn’t closed well. Try this: var array1 = [1,2,3] var l for (l = 0; l < (array1.length-1); l++) { if (array1[l] == 1) { alert(“what?”) } } You had this if( … ) { { Should be if( … ) { } 0 solved Unexpected end of input Error in a … Read more
document.querySelectorAll(‘#board > div’).forEach(dv=>console.log(dv.id)) <div id=”board”> <div id=”sss” class=”card”><img src=”https://stackoverflow.com/questions/61471086/img/sss” alt=”sss”></div> <div id=”ssa” class=”card”><img src=”https://stackoverflow.com/questions/61471086/img/sss” alt=”sss”></div> <div id=”ssb” class=”card”><img src=”https://stackoverflow.com/questions/61471086/img/sss” alt=”sss”></div> </div> 0 solved How to get the ids of the children using the parent id?
Pure JS solution. jQuery solution would be easier. I had to add a helping function, that’s why it looks a little bit messy. var elems = document.getElementsByTagName(‘li’); function clear() { Array.from(elems).forEach(v => v.classList.remove(“active”)); } Array.from(elems).forEach(function(v) { v.addEventListener(‘click’, function(event) { event.preventDefault(); clear(); this.classList.add( “active” ); }); }); #navigation { margin-top: 20px; width: auto; display: block; list-style: … Read more
your javascript code of google map and marker should be inside window.onload function <script type=”text/javascript”> var locations = <?php echo $locations ?>; window.onload = function(e){ var map = new google.maps.Map(document.getElementById(‘regularMap’), { zoom: 10, center: new google.maps.LatLng(-33.92, 151.25), mapTypeId: google.maps.MapTypeId.ROADMAP }); var infowindow = new google.maps.InfoWindow(); var marker, i; for (i = 0; i < locations.length; … Read more
Give the p tags the id as the value of the options, and show the p tag when selected option has the value which is equal to the id of p $(‘p’).hide(); $(‘#1’).show(); $(‘select’).change(function() { $(‘p’).hide(); var a = $(this).val(); $(“#” + a).show(); }) <script src=”https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js”></script> <label for=”form_name”>Title</label> <select class=”bootstrap-select”> <option value=”1″ selected=”selected”>Feature 1</option> <option … Read more
class Menu extends React.Component { render() { // you can use this.props.history anywhere in the class const { history } = this.props; return <AppBar>…</AppBar> } } export default withRouter(Menu); solved React stateless functional component to class Component
Your problem is in resetting lightstand. by putting var in front of it inside thew click event handler, you are creating a new lightstand variable in the that function’s scope. Remove var there and JavaScript will move up the scope chain to find the outer lightstand and set it. $(document).ready(function(){ var lightstand = 0; //KEEP … Read more
$carname; does not in fact do anything. It’s neither using the variable for any operation, nor is it assigning anything to it. In PHP variables are “initialised” by assigning something to them. If anything, $carname; is the same as echo $carname; without the echo, it’s just a NOOP. In fact, the first line doesn’t do … Read more
The devtools console gives it away: Mixed Content: The page at ‘https://rowansdabomb.github.io/‘ was loaded over HTTPS, but requested an insecure script ‘http://ajax.aspnetcdn.com/ajax/jQuery/jquery-1.12.2.min.js‘. This request has been blocked; the content must be served over HTTPS. Your page is being served via HTTPS (which is great) but it tries to load jQuery via HTTP, which is not … Read more
You can alert the user using windows load function. window.onload = function () { alert(‘Package Successfully Booked!’); } or you can do it this way <html> <head> <script> function showAlert() { alert(“Package Successfully Booked!”); } </script> </head> <body onload=”showAlert()”> </body> </html> solved Javascript alert and back with php
I Find Answer jQuery(document).ready(function(){ jQuery(‘#more_senior’).click(function(){ var finance_cont1=jQuery(‘.senior-contact’).length; var finance_cont=finance_cont1+1; var add_new ='<div class=”form-group senior-contact” id=”senior_’+finance_cont+'”><div class=”col-sm-9″><label for=”firstName” class=”control-label”>Senior Mgmt. Contact#</label></div><div class=”col-sm-9″><input type=”text” id=”seniormgmt’+finance_cont+'” name=”seniormgmt[]”placeholder=”Senior Mgmt. Contact” class=”form-control” autofocus></div>\n\ <a href=”#” class=”delete_png”>Remove</a></div>’; jQuery(add_new).insertAfter( “#senior_”+finance_cont1 ); delete_fields(); }); function delete_fields(){ $(‘.delete_png’).on(“click”,function(){ var class_name=jQuery(this).parent().attr(‘class’); class_name=class_name.split(‘ ‘); var id_name=jQuery(this).parent().attr(‘id’); var finance_cont2=jQuery(‘.’+class_name[1]).length; var finance_cont3=finance_cont2-1; var id_first=id_name.split(‘_’); $(‘#’+id_name).remove(); delete_fields(); }); } … Read more
You can use filter to get the values that occur twice. var arr = [0, 1, 2, 2, 3, 3, 5]; var dups = arr.filter ( (v,i,a) => a.indexOf(v) < i ); console.log(dups); In comments you stated you would only have doubles, but no values that occur more than twice. Note that the above would … Read more
Sure but our (or at least my) human brain doesn’t like reading it 😉 num1 = num2 != 0 ? num2 : num3 != 0 ? num3 : num4 != 0 ? num4 : num5 != 0 ? num5 : “” spacing is not required just makes it more readable. 5 solved How to make … Read more