You need two different function names, as declaring the second one will overwrite the first. Change the name to something more declarative (say, toggleGender) See my change here. solved how to use jquery hiding two fields
There are two solutions here – one is the algebra that solves the problem you’re actually presenting (because estimation isn’t required here), and the other is the code for doing the estimating if it WERE required. Algebra: If we express the markup rate and both tax rates as 1 + increase%, it makes our math … Read more
The problem you’re facing here is that your regex is replacing newline characters with a space before the final replacement of newline characters by <br /> elements occurs. As a result, in cases where your hashed string is preceded by a newline, the highlight will appear on the previous line, rather than correctly being placed … Read more
Give this way: $(function () { // Give the below one, or use the perfect selector for your first <li> $(“li”).first().trigger(“click”); }); Or if you are making it using <select> tag, you need to handle it in a different way: $(function () { // Give the below one, or use the perfect selector for your … Read more
The functionality logic : when a button is pressed we check if it has the red class (as all the elements, buttons and the other divs, will receive the red class at some point). if it has that class then it will be toggled (it will be removed from all the buttons and the other … Read more
You can do something like this const data = [{date: 2021,name: ‘New York’,price: 452}, {date: 2020,name: ‘New York’,price: 452}, {date: 2021,name: ‘Oregon’,price: 452}] const result = Object.values(data.reduce((res, {name,…rest}) => { return { …res, [name]: { name, values: […(res[name] || {values: []}).values, rest] } } }, [])) console.log(result) solved JavaScript: Convert array of objects into array … Read more
Bitwise XOR assignment (^=) The bitwise XOR assignment operator (^=) uses the binary representation of both operands, does a bitwise XOR operation on them and assigns the result to the variable. Source: MDN 1 solved what does ^= mean in js [duplicate]
Json comes from J ava S cript O bject N otation. It’s a javascript-compatible format, so you can loop through it, and access it as you need. In other words, you do can get array[0][1][1]. If what you’re asking for is how can you receive a JSON in a string and convert it to an … Read more
I think you might mean “how to check if at least one checkbox is checked?” <div class=”a_list”><input type=”checkbox” /><p>Testing A list </p></div> <div class=”a_list”><input type=”checkbox” /><p>Testing A list </p></div> <div class=”a_list”><input type=”checkbox” /><p>Testing A list </p></div> <div class=”a_list”><input type=”checkbox” /><p>Testing A list </p></div> if (!$(“.a_list input:checked, .b_list input:checked”).length){ alert(“Please make a selection”); } inputs do … Read more
In order to achieve what you want this will do the job: <html> <head> <script src=”https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js”></script> <script> $(document).ready(function() { $(‘#myButton’).on(‘click’,function(){ alert(“i clicked it”); }); }); </script> </head> <body> <button id=”myButton”>Click Me!</button> </body> </html> $(document).ready is used to execute your code just after your page is rendered, then $(‘myButton’) will get any element with an id … Read more
Include jquery ,jquery ui only work with jquery <script src=”https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js”></script> <link rel=”stylesheet” href=”https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.1/themes/smoothness/jquery-ui.css” /> <script src=”https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.1/jquery-ui.min.js”></script> <script> $(function() { $(“#dp1”).datepicker(); }); </script> Fiddle 0 solved JQuery DatePicker calendar does not appear
It returns 5 on first iteration if you pass 4 to it. In general it returns n + 1 for any n > 1. Following the code path, it can be unrolled into product = 1 n > product // true, loop product *= n // so product is n product++ // end of loop, … Read more
You have a ? quantifier for ( and ) in your regex, which matches your parentheses for zero or one times. Simply removing it will do the trick. var format = /^\(([0-9]{3})\)[ ]?([0-9]{3})[-]?([0-9]{4})$/; Have a test for it here 1 solved Regex for Phone Number validation in JavaScript [closed]
you have several options, and i will list them right below, though i really recommend doing it by yourself if you have the time and resources, it will look better and fill much more natural than using a library (that usually just changes the mix-blend-mode in your css. darkmode.js – I believe that they are … Read more
My suggestion for you: free code camp function getPassedUsers() { var rr = [“a”, “b”]; var xx = [“c”]; return { rr: rr, xx: xx, }; } function ABC() { var data = getPassedUsers(); console.log(data.rr); console.log(data.xx); // you should first call `getPassedUsers` function // so `getPassedUsers` generate that data and return it for you // … Read more