String ts = “2019-01-21T05:56:46.000Z”; String date = ts.split(“T”)[0]; String[] splitDate = date.split(“-“); int day = Integer.parseInt(splitDate[2]); String month = “”; switch(Integer.parseInt(splitDate[1])) { case 1: month = “JAN”; break; case 2: month = “FEB”; break; . . . } System.out.println(“Day: ” + day + “, Month: ” + month); 1 solved How to get month and … Read more
If you pass an ArrayList to a function it passes a pointer back to the original list. That means any updates in the method will be updating your original ArrayList because they are the same thing. ArrayList<String> list2 = new ArrayList<String>(list); That makes a copy of list and saves it into list2. list and list2 … Read more
You’re already using an if statement. That’s the key to what you want. int a = Integer.parseInt(cijenaIgraca.getText()); int b = Integer.parseInt(kapital.getText()); if(b < a) { this.porukica.setText(“Usli ste u minus, imacete troskove!”); } else { String c = String.valueOf(b-a); this.kapital.setText(c); } Just add an else part as shown so the subtraction will only happen in that … Read more
Sorry this might be slightly off, but it’s the best that I can do with the amount of code that’s provided in Java 8 (and without actually reading through the provided Github repo): private void showNoMoreCards() { showContent((layoutBuilder) -> { layoutBuilder.row((rowBuilder) -> { rowBuilder.label(LEFT_MARGIN, “Congratulations, you’ve reviewed all the cards for now!”); }); }); } … Read more
This works for me. public static void main(final String[] args) { final String input = “aaaab aOa baaab c”; final String[] sections = input.split(” “); final int length = 3; final List<String> list = new ArrayList<>(); for (final String section : sections) { for (int i = 0; i < section.length(); i++) { if (section.length() … Read more
Just change this code: jObject = new JSONObject(result); if (jObject.has(“error”)) { String aJsonString = jObject.getString(“error”); Toast.makeText(getBaseContext(), aJsonString, Toast.LENGTH_SHORT).show(); } else { Toast.makeText(getBaseContext(), “Login Successful”, Toast.LENGTH_SHORT).show(); } } catch (JSONException e1) { // TODO Auto-generated catch block e1.printStackTrace(); Toast.makeText(getBaseContext(),result+”” , Toast.LENGTH_SHORT).show(); } So by this code, if your response is not JSON it will throw exception … Read more
Yes, if you have both Kotlin and Java files in your project, you can refer and create new objects of Kotlin class in Java. This shows how you can setup such a project in Maven: https://www.baeldung.com/kotlin/maven-java-project solved How can we use Kotlin object with Java controllers? [closed]
Closing the Scanner also closes the input stream it’s scanning — in this case System.in. Hence, when you subsequently call getYear(), it finds the input stream System.in already closed. One way to avoid this is to use the same Scanner in both methods, by passing it as an argument to the methods. From the Java … Read more
Get it from one, put it in another al_strings1.add(al_strings2.get(fromPosition)); the same as doing Object itemFromListTwo = al_strings2.get(fromPosition); al_strings1.add(itemFromListTwo); 3 solved java add item from a arraylist to another arraylist [closed]
You can find the number of common characters by the following method. I have changed p to int bt1.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { ArrayList<Character> charArray1 = new ArrayList<Character>(); ArrayList<Character> charArray2 = new ArrayList<Character>(); for (char character : st1.toString().toCharArray()) { charArray1.add(character); } for (char character : st2.toString().toCharArray()) { charArray2.add(character); } for (Character … Read more
It is a variation of Subset-Sum problem – with an additional constraint on the size of the subset (larger then 1). The problem is NP-Complete, but for relatively small integers can be solved using Dynamic Programming in pseudo-polynomial time. A possibly simpler alternative which is feasible for small arrays is brute-force – just search all … Read more
(D) It does not compile 😉 The second catch block is unreachable. If you turn it around, and catch Y first you still should get a compiler warning, as Z is a checked exception and the compiler will detect that only the first catch clause can be reached. But the example will work, and “Error … Read more
One solution is to create an array of integers that is the same size as the number of items in your listview. ListView has a method called onItemClick() that tells you which position is clicked. You can use this method to increment the value at the appropriate index of your array. 0 solved ListView Item … Read more
Not tested with data set but checking to the source codes of compareTo and matches it seems compareTo would be faster as matches then again calls Pattern.matches and includes other function calls as well (since matches takes regex as input – regex compilation puts extra overhead. Though since matches accepts regex as well it has … Read more
You can have an if statement in a while statement, etc, and instead of doing else, you can do: if(!bool) return “bool isn’t true”; Instead of doing if(bool){}else{return “bool isn’t true”;} Replace bool with whatever value you want to compare. You may replace bool with things like x>y(if x is greater than y) or a … Read more