java

[Solved] seprate object data via coma for every item but not last

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Answer 1.Declared a array list. List<String> productPrice = new ArrayList<String>(); 2.Stored a string object in that array list fname = obj1.getPrice(); productPrice.add(fname); 3.And in last used text utils for joining that array list items via comma. android.text.TextUtils.join(“,”, productPrice); solved seprate object data via coma for every item but not last

[Solved] Open PDF Automatically After Downloaded

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Thanks to @blackapps for the suggestion. I found out that the answer of my silly question is quite simple. I insist in using URLUtil.guessFileName(url,contentDisposition,mimeType)) because when I download the pdf file, the downloaded filename will be the same with the uploaded filename in my client’s website. So what I just did is adding this equation … Read more

[Solved] Difference between all java life cycles

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http://maven.apache.org/ref/3.5.0/maven-core/lifecycles.html lists 3 lifecycles: default (briefly, this is compile -> test -> package (jar/war/ear/…) -> install -> verify -> deploy) clean (just clean) site (generates project documentation and reports) solved Difference between all java life cycles

[Solved] Handler as a method parameter

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From dispatchGesture doc, callback AccessibilityService.GestureResultCallback: The object to call back when the status of the gesture is known. If null, no status is reported. handler Handler: The handler on which to call back the callback object. If null, the object is called back on the service’s main thread. That basically means, if you don’t provide … Read more

[Solved] How to convert an array of numeric values as strings to an array of bytes?

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Do use Byte.parseByte(String) to do this: public static byte[] toByteArray(String[] arr) { byte[] res = new byte[arr.length]; for (int i = 0; i < arr.length; i++) res[i] = Byte.parseByte(arr[i]); return res; } P.S. In Java byte values are [-128; 128). Therefore “128” will throw java.lang.NumberFormatException: Value out of range. Value:”128″ Radix:10. The you have to … Read more

[Solved] button doesn’t click in android studio

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Your Button clicked properly but the main thing is you did not set fact value to TextView. #. As you have declared Button and TextView outside onCreate(), no need to declare it again inside onCreate(). Use: mfactbutton = (Button) findViewById(R.id.button); mfacttext = (TextView) findViewById(R.id.textView2); Instead of: Button mfactbutton = (Button) findViewById(R.id.button); TextView mfacttext = (TextView) … Read more

[Solved] What is wrong with this code? App should get the location

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The javadoc for onCreate(savedInstanceState) states: savedInstanceState Bundle: If the activity is being re-initialized after previously being shut down then this Bundle contains the data it most recently supplied in onSaveInstanceState(Bundle). Note: Otherwise it is null. You are getting an NPE when you call savedInstanceState.getString, with a message that tells you that savedInstanceState. Solution: modify your … Read more

[Solved] if ( l

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You’re calling A.get(). That returns a java.lang.Object. You’re trying to access the key attribute f this object. But there is no attribute key in the class Object. Hence the error. You’re probaly using raw types, i.e. using a List instead of a List<MyClassWhichHasAKeyAttribute>. Don’t use raw types. There are several other potential explanations, but since … Read more

[Solved] Why Protection() Constructor is getting executed multiple times? (Especially, base constructor getting executed twice in the beginning of the output) [closed]

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The Protection constructor gets executed multiple times because you instantiate multiple objects of Protection. Each time you call new Protection(); the Protection constructor runs. You call it first in Demo, then you instantiate Derived and since Derived extends Protection so the Protection constructor gets called once more. And finally when you instantiate SamePackage and SamePackage … Read more