value is an array of integer, it can’t be zero. Any element in the array could be zero. If you are trying to determine if the array is null, then you could change the check to be: if (value == null) { Environment.Exit(1); } 1 solved Define if statement for property in C# [closed]
In the first code fragment, you are not assigning to d at all. Assignment (=) operator assigns the rvalue (right hand side) to the lvalue (left hand side). This is very standard syntax. solved if-else statement only works in a specific order and I don’t know why [closed]
It shouldn’t continue, it should throw a NullPointerException that you may intercept in the catch block. When you try if (!spnOptionSelectedTypes.equals(null)) it should throw this exception because spnOptionSelectedTypes is null so it is not a String and does not have any equals() method. Edit: It allows the first if to pass because it has 2 … Read more
Wouldn’t this be easier? <?php switch ($_GET[‘part’])) { case ‘1’: ## part 1 ## Some content break; case ‘2’: ## part 2 ## Some content break; case ‘3’: ## Part 3 ## Some content break; default: header(‘Location: index.php?part=1′); } ?> 2 solved if statement with $_GET[‘part’]
Here is what worked for the logic of showing updated post date and time if post is updated and if not just show published date and time for WORDPRESS <?php $u_time = get_the_time(‘U’); $u_modified_time = get_the_modified_time(‘U’); if ($u_modified_time >= $u_time + 86400) { echo ” [UPDATED] “; the_modified_time(‘F j, Y’); echo ” at “; the_modified_time(); … Read more
I doubt any of your samples work, because you need to show the toast: Toast.makeText(context, “ABC”, Toast.LENGTH_SHORT).show(); solved If statement in android is not working [closed]
if (a.equalsIgnoreCase(“yes”)) { … } (or equals if you want to match “yes” exactly) 1 solved how to make an if statement then send a message [closed]
try if($_GET[“menu”] == “mMenu-Point”) : At the moment you are setting (=) $_GET[“menu”] not comparing it (==) 2 solved Php condition doesn’t work for html [closed]
It’s because the input() function takes string input. Either convert the input into int using int() function OR if x == ‘1’: # your stuffs elif x == ‘2’: # your stuffs The problem is your last condition: elif >=0 because no matter which integer I type it’s always greater than 0 isn’t it? Thus, … Read more
The line printf(“%d:00”); should be: printf(“%d:00”, hour); See if you can turn up your compiler warning level, modern compilers tend to be able to warn about this sort of mistake. 2 solved Range of IF statements in C programming
Try following this one:- if(strDistance.equals(“”)||strTime.equals(“”) { txtError.setText(“Please insert the distance and time”); } solved android-if condition doesn’t work
First open an ifstream to open your file then check for the string: #include <iostream> #include <fstream> #include <string> using namespace std; int main () { string line; ifstream myfile (“example.txt”); if (myfile.is_open()) { while ( getline (myfile,line) ) { if(line.find(“the string to find”) != string::npos) { //line found, do something } } myfile.close(); } … Read more
d1 is not initialized in the else block and in only in the if or else if blocks, so if all the statements in if() and else if() blocks are false then the controller comes to the else block, where d1 is still not initialized. so when you try to access it inside system.out.println(), the … Read more
restavracija is a type, not an object. You have to instantiate it to produce an object. In this particular case, it looks like you’re expecting an array of them, and you want to call that array polje. Such an array declaration will look something like: restavracija polje[10]; Accessing element i in that array will then … Read more
Often if you have a unique list of items that you want to associate with some other item, a Dictionary is a good solution. Each item in a dictionary is called a KeyValuePair, and consists of two parts: a unique key, which in this case would be the name, and a value associated with that … Read more