[Solved] How does http/ssh protocol work? [closed]
As application-level protocols, they simply define what data is transmitted via lower-level protocols like IP (where routing details are handled). 4 solved How does http/ssh protocol work? [closed]
As application-level protocols, they simply define what data is transmitted via lower-level protocols like IP (where routing details are handled). 4 solved How does http/ssh protocol work? [closed]
You are not allowed to do network operations with the Main (UI) thread. There are several ways of using background threads. I would recommend using AsyncTask since it has a nice structure which is easy to understand. http://developer.android.com/reference/android/os/AsyncTask.html Here is an SO example also: AsyncTask Android example Should be a lot more available on Google. … Read more
A viable method would be to create a simple API. If you supply FTP credentials with your app, chances are it will be hacked. If you create a simple HTTP API, you can assign a unique API key to every client, and if someone uses it for spam or whatever, you can just ban them … Read more
Can I invent my own HTTP Status Code for when an entity is updated and the server returns a representation of the updated entity? solved Can I invent my own HTTP Status Code for when an entity is updated and the server returns a representation of the updated entity?
Sending a body with a GET request is not supported by HTTP. See this Q&A for full details. But if you really want to do this, even though you know it’s wrong, you can do it this way: iKnowThisBodyShouldBeIgnored := strings.NewReader(“text that won’t mean anything”) req, err := http.NewRequest(http.MethodGet, “http://example.com/foo”, iKnowThisBodyShouldBeIgnored) if err != nil … Read more
I would do the opposite. Instead of removing http:// or https:// and then adding it again, I would just check if the string starts with http:// or https://, and add http:// only if it doesn’t. Something like: if($rr[‘site’]) { $url = preg_match(‘/^https?:\/\//’, $rr[‘site’]) ? $rr[‘site’] : ‘http://’.$rr[‘site’]; echo ‘<a target=”_blank” href=”http://’.$url.'” class=””>’.$url.'</a>’; } 1 solved … Read more
If you don’t want to fight with the JRE internal HttpURLConnection then you should have a look at the HttpClient from Apache Commons: org.apache.commons.httpclient final HttpClient httpClient = new HttpClient(); String url; // your URL String body; // your JSON final int contentLength = body.length(); PostMethod postMethod = new PostMethod(url); postMethod.setRequestHeader(“Accept”, “application/json”); postMethod.setRequestHeader(“Content-Type”, “application/json; charset=utf-8”); … Read more
If you are talking about Java web applications, then they need to run Java code on the web server. A static web server alone won’t do that. That is the same situation with all other server-side programming environments as well (although some of them work via a plugin that is directly embedded into the Apache … Read more
{} is just an empty Json object, and it will decode fine to your Operandsstruct, as the struct is not required to have anything in the Operands array. You need to validate that yourself, e.g. err := json.NewDecoder(req.Body).Decode(&operands) if err != nil || len(operands.Values) == 0{ solved Golang not producing error when decoding “{}” body … Read more
This should work: console.log(‘value of POST parameter surname: ‘+req.body[dynamicName]);. By doing a dot notation, you are referring to dynamicName property, not the value it holds as a variable. 0 solved JavaScript: dynamic name of POST parameter
let url = “192.168.1.1/api/project” var header = [String:String]() header[“accept”] = “aplication/json” header[“key”] = “David” let reqParam = [“project”:[“title”:”Test Title”,”description”:”Test description for new project”,”priority”:false,”category_id”:1,”location_id”:1]] Alamofire.upload(multipartFormData: { multipartFormData in for (key, value) in reqParam{ do{ let data = try JSONSerialization.data(withJSONObject: value, options: .prettyPrinted) multipartFormData.append(data, withName: key) }catch(let err){ print(err.localizedDescription) } } },usingThreshold:UInt64.init(), to: url, method: .post, headers: … Read more
You could send variables in map. For example: package main import ( “bytes” “fmt” “text/template” ) func main() { t, _ := template.New(“hi”).Parse(“Hi {{.name}}”) var doc bytes.Buffer t.Execute(&doc, map[string]string{“name”: “Peter”}) fmt.Println(doc.String()) //Hi Peter } solved Html template use on golang
This is HTTP. You can’t just open a socket and start reading something. You have to be polite to the server and send a request first: socket.getOutputStream().write(“GET /index.html HTTP/1.0\n\n”.getBytes()); socket.getOutputStream().flush(); Then read a HTTP response, parse it, and get your html page back. EDIT I wrote what to do with sockets only because it was … Read more
As @cybermonkey said, you should communicate via HTTP POST. Http Post lets you send data (large bits of data), you can use the headers actively to determine response status etc. When using POST, I would recommend transporting the strings in JSON-format. JSON Allows you to serialize and deserialize objects, arrays and strings. Can be serialized … Read more
You need to use the below public class HttpGetWithBody extends HttpEntityEnclosingRequestBase { @Override public String getMethod() { return “GET”; } } HttpGetWithBody getWithBody = new HttpGetWithBody (); getWithBody.setEntity(y(new ByteArrayEntity( “<SOMEPAYLOAD FOR A GET ???>”.toString().getBytes(“UTF8”)));); getResponse = httpclient.execute(getWithBody ); Import needed will be org.apache.http.client.methods.HttpEntityEnclosingRequestBase; solved Send content body with HTTP GET Request in Java [closed]