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You can do something like this: Pattern pat = Pattern.compile(“((?:[^\u0003]*\u0003){30}[^\u0003]*)\u0003(.*)”); Matcher matcher = pat.matcher(input); if (matcher.matches()) { String leftPart = matcher.group(1); String rightPart = matcher.group(2); } The pattern works as follows: The first capture group finds a substring with exactly 30 occurrences of the separator \u0003; the subpattern that finds a substring with no separators, … Read more

Introduction String manipulation is a common task in programming, and Java provides a number of ways to split a string at a specific separator. In this article, we will discuss how to split a string at the n’th occurrence of a specific separator in Java. We will look at various examples and discuss the different … Read more