[ad_1] Preety straight forward answer for you… <?php $fp = fopen(“counters/counterlog.txt”, “r”); $count = fread($fp, 1024); fclose($fp); $count = $count + 1; echo “<p>Pageview: ” . number_format($count) . “</p>”; // <=== $fp = fopen(“counters/counterlog.txt”, “w”); fwrite($fp, $count); fclose($fp); ?> 1 [ad_2] solved php add counter with thousands separator [closed]
[ad_1] Assuming you have a pandas dataframe, one option is to use pandas.crosstab to return another dataframe: import pandas as pd df = pd.read_csv(‘file.csv’) res = pd.crosstab(df[‘X’], df[‘Y’]) print(res) Y 0 1 X 0 3 7 1 1 3 A collections.Counter solution is also possible if a dictionary result is required: res = Counter(zip(df[‘X’].values, df[‘Y’].values)) … Read more
[ad_1] how are you? I have made 3 alterations in 2 classes. have a look to see if it will work for you. //Computers turn to roll the dice. public void computerTurn() { computerTurnNumber = 0; // here turnScore = 0; System.out.println(“Computer’s turn: “); while (computerTurnNumber < 20) { // here is the amount of … Read more
[ad_1] With the current code you have you don’t even need to use a counter. Instead you can load FoundAt into an array and then use the Ubound to get the total count. Note you have to add 1 since the array is 0 based. Add these lines before your final Msgbox Dim iCount() as … Read more
[ad_1] Not a lot of code needed, just a small helper function to calculate days difference and then a replace content with whatever you want. Full sample: <html> <div id=”counter” /> <script type=”text/javascript”> function daysDifference($startDate, $endDate) { oneDay = 24*60*60*1000; return Math.ceil(($endDate.getTime() – $startDate.getTime()) / oneDay); } // 2015/01/01 $startDate = new Date(2015, 0, 1); … Read more
[ad_1] If you only want to increment unless some condition is met, you should mention that in your code. Using the postfix foo() unless condition(); syntax means the condition will only refer to the previous statement, not the entire scope ( which would arguably be insane to parse ). So print ‘…’ unless $foo is … Read more
[ad_1] This has to do with the scope of your variable: From Java Language Specification, Section 6.3: The scope of a declaration is the region of the program within which the entity declared by the declaration can be referred to using a simple name, provided it is visible. A declaration is said to be in … Read more
[ad_1] Below one is solution I believe. Sure there is more room to refactor it, you can start from here. a = [“red”, “orange”, “green”, “red”, “yellow”, “blue”, “green”] a.reject {|e| ![‘red’, ‘green’].include? e } .each_cons(2) .select{|e| e == [‘red’, ‘green’]} .size A more artistic version. def neither_red_nor_green e ![‘red’, ‘green’].include? e end def red_followed_by_green … Read more
[ad_1] I would do it like this: >>> fst = {‘A’: 5, ‘B’: 6, ‘C’: 8} >>> snd = {‘A’: 4, ‘B’: 9, ‘E’: 2} >>> out = {k: fst[k] + snd[k] for k in fst.keys() & snd.keys()} >>> out.update({k: fst[k] if k in fst else snd[k] for k in fst.keys() ^ snd.keys()}) >>> out … Read more
[ad_1] Are you referring to something like this? int counter = 0; //in event if(textbox1.ToString().Equals(textbox2.ToString())) { counter++; } 2 [ad_2] solved How to incrase counter value when both textbox value are equal in onClick using C# [closed]
[ad_1] I would suggest a simplified “architecture”. Your functions to get the user and computer choices should return values that can be compared. import random CHOICES = (‘rock’, ‘paper’, ‘scissors’) def get_user_choice(): choice = input(‘Rock, paper, or scissors? ‘) choice = choice.lower().strip() if choice not in CHOICES: print(‘Please select one of rock, paper, or scissors’) … Read more
[ad_1] this is the way to wrap your already exist php code in table, try it: $e = array(“item1”, “item2”, “item3”, “item4”, “item5”, “item6”, “item7”, “item8”, “item9”, “item10”, “item11”, “item12”); $i = 0; echo “<table border=1><tr>”; //tr to start the 1st row foreach ($e as $value) { $i++; if ($i % 3 != 1) echo … Read more